Answer:
The distance the plane covered while it was accelerating is 80,633.3 m
Explanation:
Given;
initial velocity of the plane, u = 90 m/s
acceleration of the plane, a = 1.5 m/s²
final velocity of the plane, v = 500 m/s
The distance covered by the plane is given as;
v² = u² + 2ad
where;
d is the distance covered by the plane;
500² = 90² + 2(1.5)d
500² - 90² = 3d
241900 = 3d
d = 241900 / 3
d = 80,633.3 m
Therefore, the distance the plane covered while it was accelerating is 80,633.3 m
Answer:
The three remaining light bulbs will remain dark.
Explanation:
Current can only flow if there is a complete circuit through all of the series elements. With one element removed, no current can flow, so the remaining light bulbs cannot light up.
Answer:
the force of attraction between the two charges is 4.2 x 10⁹ N.
Explanation:
Given;
the magnitude of first charge, q₁ = 0.06 C
the magnitude of the second charge, q₂ = 0.07 C
distance between the two charges, r = 3 m
The force of attraction between the two charges is calculated as ;
where;
k is Coulomb's constant = 9 x 10⁹ Nm²/C²
Therefore, the force of attraction between the two charges is 4.2 x 10⁹ N.
