Answer:
3 hours
Explanation:
180 divided by 60 (mph means miles per hours by the way)
Answer:
the best graph to find the acceleration is v-t since calculating the slope averages the different experimental errors.
Explanation:
The different graphics depending on time give various information, let's examine what we can get from some
Graph of x -t. from this graph we can obtain the speed through the slope, but the acceleration is not directly obtainable
v-t chart. We can get the acceleration not through the slope and the distance traveled by the area under the curve. Obtaining acceleration is very accurate since it is an average that avoids possible errors in measurements. This is the best graph to find the acceleration
Graph of a-t In this graph the acceleration is a point on the Y axis, it gives some errors because it depends strongly on the possible experimental errors.
In conclusion, the best graph to find the acceleration is v-t since calculating the slope averages the different experimental errors.
Assume that the ball rolls to the right.
From the velocity-time graph, the acceleration is
a = (0 - 10 m/s)/(4 - 0 s) = -2.5 m/²
Part (a)
Because the mass of the ball is 25g or 0.025 kg, the force that the road exerts on the ball is
F = (0.025 kg)*(-2.5 m/s²) = -0.0625 N
The force is negative because it acts in opposition to the motion of the ball.
Answer: 0.0625 N to the left.
Part (b)
The direction of the force exerted by the road is to the left because it opposes the motion of the ball to the right.
Part (c)
The unit force is 1 N (Newton), with the dimension (kg-m)/s².
Answer:

10.63952 V
Explanation:
= Number of turns = 200
= Magnetic flux = 
= Engine angular speed = 
Alternator angular speed is given by


Induced emf is given by

The function is 
The induced maximum emf is 10.63952 V
Answer:
Radius of bigger loop(R) =4.5cm
Explanation:
Consider a circular path of radius r around the wire. The magnetic field along that path is given by
;
∫B*dl = k*I where I is the current enclosed. From symmetry, ∫B*dl = 2*π*r*B
B = K*I/r, so the magnetic field varies inversely as the loop radius and directly as the current.
The smaller loop current to radius ratio is 12/2.7
The bigger loop current to radius ratio is = 20/R
12/2.7 = 20/R
R = (20 * 2.7)/12
R=54/12
R=4.5cm