Question

Fill in the table (parallel circuit)

Answer 1

I don't see a table anywhere near here, but I think I can show you how to calculate those quantities.

From your description, I'm picturing two 32-ohm resistors in parallel, connected across a 96-volt battery or other power supply.

In parallel, each resistor has the same voltage across it.  So it might be easier
if we begin by considering them separately:

Current through one resistor = V/R = 96/32 = 3 Amperes.
Current through both of them, supplied by the battery = 6 Amperes.

Power dissipated by one resistor = I² R = (3)² (32) = 9 x 32 = 288 watts.
Power dissipated by both of them, supplied by the battery = 576 watts.

Equivalent resistance as seen by the battery = (32)² / 64 = 16 ohms. 

Check:

If the battery sees 16 ohms, then the current is V/R = 96/16 = 6 Amp.

Power supplied by the battery is (V x I) = 96 x 6 = 576 watts.

yay !

Note:
288 watts is a lot of power.  You'll need big, expensive resistors,
possibly even immersed in an oil bath, unless your resistors are
coils of resistive wire and you plan on toasting bread with them.