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sesenic [268]
2 years ago
8

A 14 kilogram beam is hinged at one end. A 6.0-kilogram triangular object and a 7.5-kilogram capital I-shaped object are placed

as shown in the figure. The dots indicate the individual centers of gravity of the beam and objects. The center of mass of the entire system must be:

Physics
1 answer:
GuDViN [60]2 years ago
5 0

Answer: 1.3 m

Explanation:

From the figure attached, 3 materials are involved. A 14 kilogram beam hinged at one end, a 6.0-kilogram triangular object and a 7.5-kilogram capital I-shaped object.

Let take the moment at the hinge axis.

The moment for the beam will be

14 × ( 0.36 + 0.53 ) = 12.6

The moment of the triangle object will be 6 × 0.36 = 2.16

The moment of capital I shape will be

7.5 × ( 0.36 + 0.53 + 1.92 ) = 21.075

The total moment = 12.6 + 2.16 + 21.075

The total moment = 35.835

The total mass = 14 + 6 + 7.5 = 27.5

The center of mass of the entire system must be:

X = total moment ÷ total mass

Substitute both in the formula

X = 35.835/27.5

X = 1.3 m.

Therefore, The center of mass of the entire system must be 1.3m

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3 years ago
You illuminate the grating in a spectrometer at normal incidence θi=0° with a beam of light that has a wavelength of 6562.8 Å. T
monitta

Answer:

a) θ₁ = 23.14 ° , b) θ₂ = 51.81 °

Explanation:

An address network is described by the expression

     d sin θ = m λ

Where is the distance between lines, λ is the wavelength and m is the order of the spectrum

The distance between one lines, we can find used a rule of proportions

     d = 1/600

     d = 1.67 10⁻³ mm

    d = 1-67 10⁻³ m

Let's calculate the angle

    sin θ = m λ / d

    θ  = sin⁻¹ (m λ / d)

First order

    θ₁ = sin⁻¹ (1 6.5628 10⁻⁷ / 1.67 10⁻⁶)

    θ₁ = sin⁻¹ (3.93 10⁻¹)

    θ₁ = 23.14 °

Second order

     θ₂ = sin⁻¹ (2 6.5628 10⁻⁷ / 1.67 10⁻⁶)

     θ₂ = sin⁻¹ (0.786)

     θ₂ = 51.81 °

3 0
3 years ago
4025.05m +20.0m +0.050004m
PIT_PIT [208]
The answer is 4,045.1 meters
5 0
3 years ago
Consider the two moving boxcars in Example 5. Car 1 has a mass of m1 = 65000 kg and a velocity of v01 = +0.80 m/s. Car 2 has a m
Amiraneli [1.4K]

Answer:

1.034m/s

Explanation:

We define the two moments to develop the problem. The first before the collision will be determined by the center of velocity mass, while the second by the momentum preservation. Our values are given by,

m_1 = 65000kg\\v_1 = 0.8m/s\\m_2 = 92000kg\\v_2 = 1.2m/s

<em>Part A)</em> We apply the center of mass for velocity in this case, the equation is given by,

V_{cm} = \frac{m_1v_1+m_2v_2}{m_1+m_2}

Substituting,

V_{cm} = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

V_{cm} = 1.034m/s

Part B)

For the Part B we need to apply conserving momentum equation, this formula is given by,

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where here v_f is the velocity after the collision.

v_f = \frac{m_1v_1+m_2v_2}{m_1+m_2}

v_f = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

v_f = 1.034m/s

8 0
3 years ago
Alexis is a scientist who is studying solid-state physics. Which activity would she most likely do as a part of this research? O
Ann [662]

Answer:

pretty sure its studying the atomic structure of a solid carbon dioxide. so c

Explanation:

8 0
2 years ago
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