Eric has a mass of 80 kg. He is standing on a scale in an elevator that is accelerating downward at 1.7 m/s2. What is the approx
1 answer:
To solve this problem it is necessary to apply the concepts related to the Force of Gravity and the Normal Force that act on the body.
The Gravity Force on Eric would be given by
To find the normal Force we must also consider downward acceleration therefore
Since the Normal Force is the Reaction Force the approximate reading on the scale is 650N
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Answer:
X-Positions: Y-Positions
x(0) = 0 y(0) = 0
x(2) = 120 m y(2) = 19.6 m
x(4) = 240 m y(4) = 78.4 m
x(6) = 360 m y(6) = 176.4 m
x(8) = 480 m y(8) = 313 m
x(10) = 600m y (10) = 490 m
Explanation:
X-Positions
- First, we choose to take the horizontal direction as our x-axis, and the positive x-axis as positive.
- After being thrown, in the horizontal direction, no external influence acts on the stone, so it will continue in the same direction at the same initial speed of 60. 0 m/s
- So, in order to know the horizontal position at any time t, we can apply the definition of average velocity, rearranging terms, as follows:
- It can be seen that after 2 s, the displacement will be 120 m, and each 2 seconds, as the speed is constant, the displacement will increase in the same 120 m each time.
Y-Positions
- We choose to take the vertical direction as our y-axis, taking the downward direction as our positive axis.
- As both axes are perpendicular each other, both movements are independent each other also, so, in the vertical direction, the stone starts from rest.
- At any moment, it is subject to the acceleration of gravity, g.
- As the acceleration is constant, we can find the vertical displacement (taking the height of the cliff as the initial reference level), using the following kinematic equation:
- Replacing by the values of t, we get the following vertical positions, from the height of the cliff as y = 0:
- y(2) = 2* 9.8 m/s2 = 19.6 m
- y(4) = 8* 9.8 m/s2 = 78.4 m
- y(6) = 18*9.8 m/s2 = 176.4 m
- y(8) = 32*9.8 m/s2 = 313.6 m
- y(10)= 50 * 9.8 m/s2 = 490.0 m
Answer:
Torque on the rocket will be 1.11475 N -m
Explanation:
We have given that muscles generate a force of 45.5 N
So force F = 45.5 N
This force acts on the is acting on the effective lever arm of 2.45 cm
So length of the lever arm d = 2.45 cm = 0.0245 m
We have to find torque
We know that torque is given by
So torque on the rocket will be 1.11475 N -m
Answer:
Maximum height reached by the rocket is
total time of the motion of rocket is given as
Explanation:
Initial speed of the rocket is given as
acceleration of the rocket is given as
engine stops at height h = 150 m
so the final speed of the rocket at this height is given as
so maximum height reached by the rocket is given as the height where its final speed becomes zero
so we will have
Now the total time of the motion of rocket is given as
1) time to reach the height of 150 m
2) time to reach ground from this height
so total time of the motion of rocket is given as