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Tatiana [17]
3 years ago
11

Eric has a mass of 80 kg. He is standing on a scale in an elevator that is accelerating downward at 1.7 m/s2. What is the approx

imate reading on the scale? Eric has a mass of 80 . He is standing on a scale in an elevator that is accelerating downward at 1.7 . What is the approximate reading on the scale? 0 N 650 N 780 N 920 N
Physics
1 answer:
Yuki888 [10]3 years ago
3 0

To solve this problem it is necessary to apply the concepts related to the Force of Gravity and the Normal Force that act on the body.

The Gravity Force on Eric would be given by

F_g = mg

F_g = (80)(9.8)

F_g = 784N

To find the normal Force we must also consider downward acceleration therefore

F_N = M(-g+a)

F_N = (80)(-9.8+1.7)

F_N = -648N

Since the Normal Force is the Reaction Force the approximate reading on the scale is 650N

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Ulleksa [173]

Answer: 88.2 J

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mass - 3kg

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gravity is 9.8kg

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4 0
3 years ago
What is one advantage of doing a field experiment instead of a laboratory experiment
Flauer [41]

It mimics the real world accurately

Explanation:

Experiments conducted in the field clearly presents the real world at it is to the scientist. Hardly can any part be controlled precisely and this gives a near to perfect scenario.

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Learn more:

Experiment brainly.com/question/5096428

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5 0
3 years ago
Does the efficiency of a motor depend on mass?
Valentin [98]

Practically yes

  • Efficiency=Output/input

So

If mass is more output may come less so it affects the efficiency practically

But thepritically it doesn't

5 0
2 years ago
Read 2 more answers
A space station, in the form of a wheel 119 m in diameter, rotates to provide an "artificial gravity" of 2.20 m/s2 for persons w
Rina8888 [55]
<span>Well, since it's in the shape of a wheel and the person walks around the edge of it, they must have a centripetal acceleration. Since a=v^2/r you can solve for "v" using 2.20 as your "a" and 59.5 as your "r" (r=half of the diameter).
</span> a=v^2/r 
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</span></span><span> After you get "v," plugged that into T=2 pi r/ v. This will give you the 1rev per sec.
</span> T=2 pi r/ v= T=(2)*(pi)*(59.5)/(11.44)= <span> <span>32.68 rev/s
</span></span> Use dimensional analysis to get rev per min (1rev / # sec) times (60 sec/min). 
 (32.68 rev/s)(60 s/min)=<span> <span>1960.74 rev/min
</span></span>
5 0
3 years ago
Which method of measurement would be accurate but lack precision?
kodGreya [7K]

Answer:

B

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the bottom meniscus may cause a wrong reading due to refraction of light

7 0
2 years ago
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