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TEA [102]
3 years ago
13

HELP ASAPP!!!! WILL GIVE BRAINLIEST! Describe the chemical structure of a cell membrane

Physics
2 answers:
MariettaO [177]3 years ago
4 0

Answer:

The plasma membrane is composed of a bilayer of phospholipids, with their hydrophobic, fatty acid tails in contact with each other. ... Carbohydrates are attached to some of the proteins and lipids on the outward-facing surface of the membrane. These form complexes that function to identify the cell to other cells.

Explanation:

Hope it answered you plz mark as Brainlist

bagirrra123 [75]3 years ago
3 0
Main components are lipids, proteins, and carbohydrates
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A Nerf gun is shot straight up from the ground with an initial velocity of 14.0 m/s. What is the total time the projectile is in
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The projectile has a height <em>h</em> at time <em>t</em> given by

<em>h</em> = (14.0 m/s) <em>t</em> - 1/2 <em>g t</em> ²

where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity. Solve for <em>t</em> when <em>h</em> = 0 :

0 = (14.0 m/s) <em>t</em> - 1/2 <em>g t</em> ²

0 = 1/2 <em>t</em> (28.0 m/s - <em>g t</em> )

1/2 <em>t</em> = 0   <u>or</u>   28.0 m/s - <em>g</em> <em>t</em> = 0

The first equation says <em>t</em> = 0, which refers to the moment the gun is first fired, so we ignore that solution. We're left with

28.0 m/s - <em>g t</em> = 0

<em>t</em> = (28.0 m/s) / <em>g</em>

<em>t</em> = (28.0 m/s) / (9.80 m/s²)

<em>t</em> ≈ 2.86 s

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Which of the following methods is the most effective in determining muscular strength if you do not want to worry about selectin
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Two vehicles approach a right angle intersection and then suddenly collide. After the collision, they become entangled. If their
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Answer with Explanation:

Let mass of one vehicle =m

Mass of other vehicle=m'

\frac{m}{m'}=\frac{1}{4}

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Velocity of other vehicle=v'=13jm/s

In x- direction

By law of conservation of momentum

mv+0=(m+m')V_x

13m=(m+4m)V_x

13m=5mV_x

V_x=\frac{13}{5}

In y- direction

By law of conservation of momentum

0+m'v'=(m+m')V_y

4m(13)=5mV_y

V_y=\frac{52m}{5m}=\frac{52}{5}

Magnitude of velocity of the wreck,V=\sqrt{V^2_x+V^2_y}=\sqrt{(\frac{13}{5})^2+(\frac{52}{5})^2}=10.72 m/s

Direction:\theta=tan^{-1}(\frac{V_y}{V_x})

\theta=tan^{-1}(\frac{\frac{52}{5}}{\frac{13}{5}})=75.96^{\circ}

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Answer:

Explanation:

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