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TEA [102]
3 years ago
13

HELP ASAPP!!!! WILL GIVE BRAINLIEST! Describe the chemical structure of a cell membrane

Physics
2 answers:
MariettaO [177]3 years ago
4 0

Answer:

The plasma membrane is composed of a bilayer of phospholipids, with their hydrophobic, fatty acid tails in contact with each other. ... Carbohydrates are attached to some of the proteins and lipids on the outward-facing surface of the membrane. These form complexes that function to identify the cell to other cells.

Explanation:

Hope it answered you plz mark as Brainlist

bagirrra123 [75]3 years ago
3 0
Main components are lipids, proteins, and carbohydrates
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A pickup truck is traveling down the highway at a steady speed of 30.1 m/s. The truck has a drag coefficient of 0.45 and a cross
Sav [38]

Answer:

The energy that the truck lose to air resistance per hour is 87.47MJ

Explanation:

To solve this exercise it is necessary to compile the concepts of kinetic energy because of the drag force given in aerodynamic bodies. According to the theory we know that the drag force is defined by

F_D=\frac{1}{2}\rhoC_dAV^2

Our values are:

V=30.1m/s

C_d=0.45

A=3.3m^2

\rho=1.2kg/m^3

Replacing,

F_D=\frac{1}{2}(1.2)(0.45)(3.3)(30.1)^2

F_D=807.25N

We need calculate now the energy lost through a time T, then,

W = F_D d

But we know that d is equal to

d=vt

Where

v is the velocity and t the time. However the time is given in seconds but for this problem we need the time in hours, so,

W=(807.25N)(30.1m/s)(3600s/1hr)

W=87.47*10^6J (per hour)

Therefore the energy that the truck lose to air resistance per hour is 87.47MJ

4 0
3 years ago
An object is falling toward Earth's surface, and its acceleration due to gravity is measured. What is NOT needed to calculate Ea
mario62 [17]

I think it's weight of the object.

7 0
3 years ago
Refraction or the bending of waves takes place when a light wave changes A) color. B) frequency. C) intensity. D) speed.
DENIUS [597]
The answer is D. speed
6 0
4 years ago
Read 2 more answers
One model for a certain planet has a core of radius R and mass M surrounded by an outer shell of inner radius R, outer radius 2R
Drupady [299]

(a) 120.8 m/s^2

The gravitational acceleration at a generic distance r from the centre of the planet is

g=\frac{GM'}{r^2}

where

G is the gravitational constant

M' is the mass enclosed by the spherical surface of radius r

r is the distance from the centre

For this part of the problem,

r=R=1.17\cdot 10^6 m

so the mass enclosed is just the mass of the core:

M'=M=2.48\cdot 10^{24}kg

So the gravitational acceleration is

g=\frac{(6.67\cdot 10^{-11})(2.48\cdot 10^{24}kg)}{(1.17\cdot 10^6 m)^2}=120.8 m/s^2

(b) 67.1 m/s^2

In this part of the problem,

r=3R=3(1.17\cdot 10^6 m)=3.51\cdot 10^6 m

and the mass enclosed here is the sum of the mass of the core and the mass of the shell, so

M'=M+4M=5M=5(2.48\cdot 10^{24}kg)=1.24\cdot 10^{25}kg

so the gravitational acceleration is

g=\frac{(6.67\cdot 10^{-11})(1.24\cdot 10^{25}kg)}{(3.51\cdot 10^6 m)^2}=67.1 m/s^2

8 0
4 years ago
Newton's Law of Universal Gravitation states that the force F between two masses, m1 and m2, is given below, where G is a consta
Hitman42 [59]

Answer:

Explanation:

According to newton's law , force between mass m₁ and m₂ at distance x is given by the following expression

F = G m₁m₂ / x²

differentiating F with respect to x , we have

dF /  d x =  ₋2G m₁m₂ / x³ .

Rate of reduction  of force ∝  1 / x³

5 0
3 years ago
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