<span>The correct answer is b. will have a one-quarter chance of being a sickle-cell-free homozygote.</span>
<span>Sickle-cell disease is an autosomal recessive disease, which means that <span>if two individuals who are heterozygous for the sickle-cell disease have child, there is a 25% chance of sickle-cell disease, 25% that the child will not carry any sickle-cell alleles, and 50% that it will have the heterozygous condition (will have an allele for disease).</span></span>
Answer:
0%
Explanation:
A bird with blue-tipped feathers (genotype Bb), when crossed with a white bird (genotype bb) can produce offspring with genotypes according to the following Punnett square:
![\begin{array}{ccc}\ \ \ &\ B&b\\\end{array}\\\begin{array}{c}b\\b\\\end{array}\left[\begin{array}{cc}bB&bb\\Bb&bb\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bccc%7D%5C%20%5C%20%5C%20%26%5C%20B%26b%5C%5C%5Cend%7Barray%7D%5C%5C%5Cbegin%7Barray%7D%7Bc%7Db%5C%5Cb%5C%5C%5Cend%7Barray%7D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7DbB%26bb%5C%5CBb%26bb%5C%5C%5Cend%7Barray%7D%5Cright%5D)
In other to have entirely blue feathers, an offspring would have to have the BB genotype. Since it is not possible to obtain this genotype by crossing the birds in question, the percent chance that an offspring will have entirely blue feathers is 0%.
Answer:
The correct answer is "by speeding up the rate at which water molecules collide with the substrate".
Explanation:
One of the most common mistakes is to think that enzymes perform the reactions directly, but enzymes act as catalyzers, and the catalysis of hydrolases works by speeding up the rate at which water molecules collide with the substrate. The enzyme lysozyme works under this same premise, and by speeding up the rate of water collision with the substrate, they lower the energy required for its substrate to reach its transition-state conformation. Which ultimately results in the substrate hydrolysis.
