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Marrrta [24]
3 years ago
7

Draw and label a rectangular prism that has a surface area of 96 square meters.

Mathematics
1 answer:
Mashcka [7]3 years ago
3 0
Basically what you need to do is draw 4 congruent rectangles and 2 comgriemt squares (The six sides of a rectangular prism). The sum of the area of these six quadrilaterals should equal 96. This would be my thought process.

Step 1: Sketch a Rectangular Prism

Step 2: Make some educated guesses on some possible side measurements for the quadrilaterals that form the prism.

Step 3: Guess and Check until the amount equals 96.

So we can guess that the sides of the rectangle might equal 2 and 3 units.

This would be 6 for the area. Times 4 for each of the 4 Rectangles. (24) and add the area of the ends of the prism (2*2*2) which is 8 and you will get 32.

Since we are looking for a surface area of 96 and not 32, we can assume that a 3*2*2 prism is not what we need. So we can try again with other values.

Let's try 6*3*3. 6*3*4 for the four rectangles plus 3*3*2 for the ends.
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Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
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Answer:

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(2)Not Transitive, (0,3) is missing

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Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

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  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

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