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3 years ago

What is the sl unit for momentum

Physics

1 answer:

mario62 [17]3 years ago

8 0

Momentum is mass times velocity and mass is measured in kg and velocity is measured per second so it really depends.

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What term is used to describe the 4 in the expression 4 Ca(NO³)²

NISA [10]

Hello,

The 4 describes the amount of calcium in that compound.

Have A Good Day.

3 0

3 years ago

In a recent survey, state voters said they were not pleased with the conditions of roads. They would like to see current roads i

topjm [15]

They are saying that they would like to see new roads and improvements, but they refuse to pay for it by giving up more money in taxes. Hope this helps :)

4 0

3 years ago

A ball is thrown vertically upward from a height of 6 feet with an initial velocity of 41 feet per second. how high will the bal

maksim [4K]

Given: Height h = 6 ft or the vertical component "y" this become the initial height, therefore if you want to know the total height of the stone with respect to the ground. you can just add up the two value below.

Initial Velocity Vi = 41 ft/s g = -32.2 ft/s² acting downward

Require: Height h = ?

Formula: y = Vf² - Vi²/2g

y = 0 - (41 ft/s)²/2(-32.2 ft/s²)

y = -1,681 ft²/s²/(-64.4 ft/s²)

y = 26.10 ft

8 0

3 years ago

Two particles, each having a mass of 3.0 mg and having equal but opposite charges of magnitude of 6.0 nC, are released simultane

algol13

Answer:

The distance that separates the two particles is 7.42 cm.

Explanation:

Given;

the mass of each particle, m = 3 mg = 3 x 10⁻⁶ kg

the magnitude of charge of each particle, q = 6.0 nC

speed of each particle, v = 5.0 m/s

$F = ma = \frac{kq^2}{r^2}$

a = v/t

where;

a is the acceleration of the two particles

v is the final velocity

t is time

v = u + gt

5 = 0 + 9.8t

5 = 9.8t

t = 5/9.8

t = 0.51 s

a = v/t

a = 5/0.51 = 9.8 m/s²

Total force on the two particles = (2m)a = (2* 3 x 10⁻⁶)9.8

F = 5.88 x 10⁻⁵ N

Substitute in the value of F in the above equation and calculate r

$F = \frac{kq^2}{r^2}$

where;

k is coulomb's constant = 8.99 x 10⁹ Nm²/c²

r is the distance of separation between the two particles

$F = \frac{kq^2}{r^2} \\\\r^2 = \frac{kq^2}{F}\\\\r = \sqrt{ \frac{kq^2}{F}} = \sqrt{ \frac{8.99*10^9*(6*10^{-9})^2}{5.88*10^{-5}}} = 0.0742 \ m$

Therefore, the distance that separates the two particles at the instant when each has a speed of 5.0 m/s, is 7.42 cm.

7 0

3 years ago

In an oscillating LC circuit, L = 4.24 mH and C = 3.02 μF. At t = 0 the charge on the capacitor is zero and the current is 2.38

Ann [662]

Answer:

a) 2.693*10^-4 C

b) 8.875*10^-5 s

c) 2.96 W

Explanation:

Given that

Inductance of the circuit, L = 4.24 mH

Capacitance of the circuit, C = 3.02 μF

Current in the circuit, I = 2.38 A

See attachment for calculations

7 0

3 years ago

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