Answer:
a)Counterclockwise
b)ω=2 rad/s
Explanation:
Given that
Object at = --2 m
r= - 2 m
Velocity pf object V = - 4 m/s
We know that
r= - 2 i m
V= - 4 j m/s
- 4 j= ω x (- 2 i)
ω should be in counter clockwise (k) to satisfy the above equation.
It means that the direction of object will in counter clockwise.
4 = ω x 2
ω=2 rad/s
So object velocity at 2 m will be 2 rad/s.
Answer:
The observed frequency by the pedestrian is 424 Hz.
Explanation:
Given;
frequency of the source, Fs = 400 Hz
speed of the car as it approaches the stationary observer, Vs = 20 m/s
Based on Doppler effect, as the car the approaches the stationary observer, the observed frequency will be higher than the transmitted (source) frequency because of decrease in distance between the car and the observer.
The observed frequency is calculated as;
where;
F₀ is the observed frequency
v is the speed of sound in air = 340 m/s
F₀ ≅ 424 Hz.
Therefore, the observed frequency by the pedestrian is 424 Hz.