Answer:
The coefficient of static friction is 0.29
Explanation:
Given that,
Radius of the merry-go-round, r = 4.4 m
The operator turns on the ride and brings it up to its proper turning rate of one complete rotation every 7.7 s.
We need to find the least coefficient of static friction between the cat and the merry-go-round that will allow the cat to stay in place, without sliding. For this the centripetal force is balanced by the frictional force.
v is the speed of cat, 
So, the least coefficient of static friction between the cat and the merry-go-round is 0.29.
Answer : 5m/s
Explanation:the formular for velocity is distance /time or you can say displacement /time. Then it would then be
100/20 =5m/s
B. It’s the same roughly at all latitudes
Energy slowly leaks outward through the radiative diffusion of photons that repeatedly bounce off ions and electrons.
<h3>What is radiative diffusion?</h3>
A radiation zone is a layer of a star's core where energy is mostly carried toward the outside by radiative diffusion and thermal conduction rather than convection.
As photons, energy passes through the radiation zone as electromagnetic radiation.
The radiative diffusion of photons that repeatedly bounce off ions and electrons progressively drains energy outward.
Hence,radiative diffusion is correct answer.
To learn more about radiative diffusion refer:
brainly.com/question/3598352
#SPJ4
Answer:
The Answer Is A,C,D
Explanation:
The gravitational pull from the moon make bigger waves'
There would be no moon for eclipses
There would be more sun and no moon
