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DochEvi [55]
4 years ago
5

At standard temperature and pressure (0 ∘C∘C and 1.00 atmatm ), 1.00 molmol of an ideal gas occupies a volume of 22.4 LL. What v

olume would the same amount of gas occupy at the same pressure and 35 ∘C∘C ?
Chemistry
1 answer:
RoseWind [281]4 years ago
4 0

Answer:

The volume would be 24, 3 L.

Explanation:

We apply the ideal gas law, we convert the unit of temperature in celsius to degrees Kelvin, we clear the volume of the formula and we use the constant R of the ideal gases that has a value of 0.082 l atm / K mol:

0°C= 273 K ---> 35°C= 273 + 35= 308K

PV=nRT   ---> V= nRT/P

V= 1 mol x 0.082 l atm / K mol x 308 K/ 1 atm= <em>25, 256 L</em>

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Given data:

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Percent yield  = ?

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C₇H₆O₃  + C₄H₆O₃      →       C₉H₈O₄ + C₂H₄O₂

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Number of moles =  1.45 mol

Now we will compare the moles of aspirin with C₇H₆O₃.

                         C₇H₆O₃           :           C₉H₈O₄

                              1                 :               1

                           1.45              :             1.45

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Mass = number of moles × molar mass

Mass = 1.45 g × 180.158 g/mol

Mass = 261.23 g

Percent yield:

Percent yield =( actual yield / theoretical yield )× 100

Percent yield =  (231 g/ 261.23 g)× 100

Percent yield = 0.88 × 100

Percent yield = 88%

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