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photoshop1234 [79]
3 years ago
14

When any salt is dissolved in water, the ionic bonds between the atoms must be broken in order for the salt to dissolve. The ene

rgy
stored up in these bonds then must be

A) convert into light
B) stored in the water
C) released to the environment
D) converted into mechanical energy
Chemistry
1 answer:
Ksju [112]3 years ago
5 0

Answer:

C released to the environment

Explanation:

I just did it in class

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Where do you think information is coded in a DNA molecule?
tester [92]

Answer:

In the nucleobases

Explanation:

The series of the nucleobases make the difference!

Check out this: https://en.m.wikipedia.org/wiki/Nucleobase

6 0
3 years ago
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19. For the reaction, 2S+ 30=2SO3, how many moles of so3 will be produced from 12.5 g 02 and excess S?
Ratling [72]

19. For the reaction, 2S+ 30=2SO3, how many moles of so3 will be produced from 12.5 g 02 and excess S?

:

For the reaction: 2S(s) + 3O2 -> 2SO2(g) How many moles of SO3 will be produced from 2.0 mol O2 and excess S?

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2 years ago
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What is the molarity of 200. mL of solution containing 4.50 moles of ZnCl2?
MariettaO [177]

Answer:

Molarity of solution = 0.9 M

Explanation:

Given data:

Moles of ZnCl₂ = 4.50 mol

Volume of solution = 200 mL

Molarity of solution = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Now we will convert the volume in L.

200 mL×1 L/1000 mL = 0.2L

M = 4.50 mol / 0.2 L

M = 0.9 M

4 0
3 years ago
When two metals touch in the mouth, a small shock is created. this is known as<br> a?
Over [174]
 <span>When two metals touch in the mouth, a small shock is created. this is known as a </span>galvanic action
7 0
4 years ago
Determine the partial negative charge on the bromine atom in a c−br bond. the bond length is 1.93 å and the bond dipole moment i
vaieri [72.5K]

Answer:

The value is x  =  0.151  \ e

Explanation:

From the question we are told that

The bond length is l  =  1.93\  \r  a =  1.93 *1 *10^{-10}  =1.93 *10^{-10}\  m

The bond dipole moment is \mu  = 1.40 d  = 1.40 *  3.33564 *10^{-30}  =  4.6699 *10^{-30} \  C \cdot m

Generally the dipole moment is mathematically represented as

\mu  =  Q *  l

Here Q is the partial negative charge on the bromine atom

So

Q =  \frac{\mu}{ l}

=> Q =  \frac{4.6699 *10^{-30}}{ 1.93 *10^{-10} }

=> Q = 2.42 *10^{-20} C

Generally

1 electronic charge(e) is equivalent to 1.60*10^{-19} C

So x electronic charge(e) is equivalent to Q = 2.42 *10^{-20} C

=> x  =  \frac{2.42 *10^{-20}}{1.60*10^{-19} }

=>     x  =  0.151  \ e

3 0
3 years ago
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