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lana [24]
3 years ago
8

What mass of copper is produced when zinc is added to a solution containing 31.9g copper ii tetraoxosulphate vi

Chemistry
1 answer:
solmaris [256]3 years ago
4 0

Answer:

12.7g of Cu

Explanation:

First let us generate a balanced equation for the reaction. This is illustrated below:

Zn + CuSO4 —> ZnSO4 + Cu

Molar Mass of Cu = 63.5g/mol

Molar Mass of CuSO4 = 63.5 + 32 + (16x4) = 63.5 + 32 + 64 = 159.5g/mol

From the equation,

159.5g of CuSO4 produced 63.5g of Cu.

Therefore, 31.9g of CuSO4 will produce = (31.9 x 63.5) / 159.5 = 12.7g of Cu

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Calculate the pOH of a solution if the concentration of hydroxide ions (OH-) is 1.9 x 10-5M?
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Answer:

9.28

Explanation:

pOH refers to a measure of hydroxide ions concentration. pOH tells about the alkalinity of a solution. If pOH is less than 7 then aqueous solutions are alkaline, acidic if pOH is greater than 7 and neutral if pOH is equal to 7.

Concentration of the hydroxide ions = 1.9 x 10-5 M

pH = -log(1.9\times 10^{-5})=4.72

pOH = 14 - pH

=14 - 4.72 = 9.28

6 0
3 years ago
How does density relate to the cold and warm air masses?
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Are these two substances the same 1.96g/ml and 2.00g/ml
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3 years ago
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3 years ago
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A container of 56mL is at STP, The pressure is increased to 3.6atm and the volume to 162 mL.
Sindrei [870]

Answer:

T2 = 2843.1   oK. This is a huge temperature.  Check it for errors.

Explanation:

Remark

This is the same question as the other one I've answered. Only the numbers have been altered.

Givens

v1 = 56 mL

P1 = 1 atm

T1 = 273o K

v2 = 162

P2 = 3.6 atm

T2 = ?

Formula

Vi * P1 / T1 = V2 * P2/T2

Solution

Rearrange the formula so T2 is on the left

T2 = V2 P2 * T1 / (V1 * P1)          Now just put the numbers in.

T2 = 162 * 3.6* 273 / (56 *1)

T2  =  159213.6/56

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3 0
3 years ago
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