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natita [175]
2 years ago
8

What is the molarity of a solution in which 0.0142 mole of Mn2(SO4)3 is dissolved in 26ml of water

Chemistry
1 answer:
valina [46]2 years ago
6 0

Answer:

.546 M

Explanation:

.0142 M / .026 = .546 M

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3 years ago
A chemist prepares a solution of silver(I) nitrate (AgNO3) by measuring out 269. micromol of silver(I) nitrate into a 300. mL vo
marishachu [46]

Answer:

The concentration of the chemist's silver(I) nitrate  solution is  0.897 mmol/L

Explanation:

<u>Step 1: </u>Data given

Number of moles AgNO3 = 269 micromol = 269 * 10^-6 mol

Volume of AgNO3 = 300 mL = 0.3 L

Molar mass of AgNO3 = 169.87 g/mol

<u>Step 2: </u>Calculate molarity of AgNO3

Molarity = number of moles per volume (in Liters)

Molarity AgNO3 = 269 *10^-6 mol / 0.3 L

Molarity AgNO3 = 8.97 * 10^-4 M

8.97 *10^-4 mol/L = 897 micromol/L = 0.897 mmol/L

The concentration of the chemist's silver(I) nitrate  solution is  0.897 mmol/L

8 0
3 years ago
You have an enzymatic reaction proceeding at the optimum pH and optimum temperature. You add a competitive inhibitor to the reac
GuDViN [60]

Answer:

Add more substrate.

Explanation:

First let's explain why all the other options are wrong:

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3 years ago
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