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4 years ago

Split 90 into two parts so tha one part is 4 times the other part

1 answer:

7 0

so, we'll end up with two parts, one being 4 times larger than the other, namely if the other is 1 slice, then the large part is 4 slices, meaning both parts will be on a 4:1 ratio.

well, simply enough, we can simply split 90 in (4+1) pieces, and then distribute accordingly to each part

$\bf \cfrac{\textit{large part}}{\textit{small part}}\qquad \qquad \stackrel{ratio}{4:1}\qquad \cfrac{4\cdot \frac{90}{4+1}}{1\cdot \frac{90}{4+1}}\implies \cfrac{4\cdot 18}{1\cdot 18}\implies \boxed{\cfrac{72}{18}}$

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Waters added or drain from a tank each day the first day 13/10 of a gallon is added to the empty tank the second day 11/10 of a

alukav5142 [94]

Answer:

2 gallons

Step-by-step explanation:

You have to find the pattern of adding and draining water for 15 days. To get there you need to subtract 2 and add 1 but keep the negative/positives the same i.e. (this is for the 10ths of gallons)

13-2=11

11+1=10

keeping the pattern for 15 days:

+13, 11,+12,-10,+11,-9,+10,-8,+9,-7,+8,-6,+7,-5,+6 = 20 (10ths of gallons)

20/10 = 2

7 0

3 years ago

3, _ 27, 81, 243 what is the next number in the sequence

Lena [83]

Answer:

3,9,27,81,243,729,2187

Step-by-step explanation:

each number up times it by 3

3x3=9 ,9×3=27, 27×3=81,81×3=243,243×3=729,729×3=2187 and so on

4 0

3 years ago

What is the multiplicity of the zero of the polynomial function f(x)=(x+5)^4

iVinArrow [24]

Multiplicity would be 4

3 0

3 years ago

Graph -x^2+x+6=0 and state the consecutive integers between which roots are located

KengaRu [80]

Answer:

The roots of given quadratic equation lies from $\begin{bmatrix}-2 , 3 \end{bmatrix}$

Step-by-step explanation:

Given as :

The quadratic equation is x² - x -6 = 0

The quadratic equation is in form of ax² + bx +c = 0

Let x1 and x2 be the roots of equation

Sum of roots

So, $x1 + x2 = \frac{-b}{a}$

And products of roots is x1 × x2 = $\frac{c}{a}$

So, $x1 + x2 = \frac{1}{1}$

Or, x1 + x2 = 1 ......A

And x1 × x2 = $\frac{-6}{1}$

Or, x1 × x2 = - 6

Now, (x1 - x2)² = (x1 + x2)²+ 4×x1×x2

Or, (x1 - x2)² = (1)²+ 4×6

Or, (x1 - x2)² = 25

So , x1 - x2 = $\sqrt{25}$ = 5 ......B

Now solve eq A and eq B

Or, (x1 + x2) + (x1 - x2) = 1 +5

Or, 2 x1 = 6

∴ x1 = 3 And x2 = - 2

Hence The roots of given quadratic equation lies from $\begin{bmatrix}-2 , 3 \end{bmatrix}$ Answer

6 0

4 years ago

PLEASE help me. I am stuck on this question for a long time.

maria [59]

Answer: Plot 1

Step-by-step explanation:

#1 Find the median of the whole set

- since there are 31 data, it is odd, we just need to find the 16th data which is 73.

- the median is 73

#2 Find the median of Less than Q2

- since there are 15 data, it is odd, we just need to find the 8th data which is 64

- the median is 64

#3 Find the median of more than Q2

- since there are 15 data, it is odd, we just need to find the 8th data which is 84

- the median is 84.

-----------------------------------

Putting it back to the box and whisker plot, it will be plot 1

6 0

3 years ago