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elixir [45]
3 years ago
9

Equations and functions

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
6 0

Answer:

first one

Step-by-step explanation:

Absolute value functions usually have that shape. The only absolute value function  out of all of the answer choices is the first one.

Anit [1.1K]3 years ago
6 0

Answer:

it is c

Step-by-step explanation:

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Workout the value of angle x.<br> Give reasons for your answer.
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so x=60°
5 0
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lubasha [3.4K]

Answer:

see below

Step-by-step explanation:

5*72*32 is not a prime factorization to begin with because neither 72, nor 32 are primes. A prime factorization for this product would be:

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and the number with this factorization is 11520.

There is a small chance that what you meant to write was this: 5\cdot 7^2 \cdot 3^2 in which case the number for this prime factorization is 2205.

5 0
3 years ago
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Which function represents the graph of h(x)=2|x+3|−1 after it is translated 2 units right?
harina [27]

\bf ~\hspace{10em}\textit{function transformations} \\\\\\ \begin{array}{llll} f(x)= A( Bx+ C)^2+ D \\\\ f(x)= A\sqrt{ Bx+ C}+ D \\\\ f(x)= A(\mathbb{R})^{ Bx+ C}+ D \end{array}\qquad \qquad \begin{array}{llll} f(x)=\cfrac{1}{A(Bx+C)}+D \\\\\\ f(x)= A sin\left( B x+ C \right)+ D \end{array} \\\\[-0.35em] ~\dotfill\\\\ \bullet \textit{ stretches or shrinks horizontally by } A\cdot B\\\\ \bullet \textit{ flips it upside-down if } A\textit{ is negative}

\bf ~~~~~~\textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if } B\textit{ is negative}\\ ~~~~~~\textit{reflection over the y-axis} \\\\ \bullet \textit{ horizontal shift by }\frac{ C}{ B}\\ ~~~~~~if\ \frac{ C}{ B}\textit{ is negative, to the right}

\bf ~~~~~~if\ \frac{ C}{ B}\textit{ is positive, to the left}\\\\ \bullet \textit{ vertical shift by } D\\ ~~~~~~if\ D\textit{ is negative, downwards}\\\\ ~~~~~~if\ D\textit{ is positive, upwards}\\\\ \bullet \textit{ period of }\frac{2\pi }{ B}

now with that template in mind

\bf h(x)=\stackrel{A}{2}|\stackrel{B}{1}x+\stackrel{C}{3}|\stackrel{D}{-1}\qquad \qquad \stackrel{\textit{C=C-2 a translation to the right}}{h(x)=2|x\boxed{+3-2}|-1} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill h(x)=2|x+1|-1~\hfill

8 0
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kolbaska11 [484]
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