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nydimaria [60]
3 years ago
14

The half-life of chromium−51 is 27.8 days. How much of a 7.6−oz sample of chromium−51 will remain after 139 days?

Mathematics
1 answer:
In-s [12.5K]3 years ago
6 0
Ending Amount = Beginning Amount / 2^n
where "n" is the number of half-lives
n = 139 / 27.8 = 5 half-lives
Ending Amount = 7.6 oz / 2^5
Ending Amount = 7.6 oz / 32
Ending Amount = .2375 ounces

Source:
http://www.1728.org/halflife.htm


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Tina has two bags of counters, Bag A and Bag B.
Korolek [52]

The probability of getting two red counters is 27.77%, the probability of getting two blue counters is 20.38%, and the probability of getting one of each color is 51.38%.

Given that Tina has two bags of counters, Bag A and Bag B, and there are 5 red counters and 3 blue counters in bag A, while there are 4 red counters and 5 blue counters in bag B, to determine, if Tina takes at random a counter from each bag, the probability of obtaining each counter, the following calculation must be made:

  • Bag A red counter = 5/8 = 0.625
  • Bag A blue counter = 1 - 0.625 = 0.375
  • Bag B red counter = 4/9 = 0.444
  • Bag B blue counter = 1 - 0.444 = 0.555
  • Two red = 0.625 x 0.444 = 0.2777
  • Two blue = 0.375 x 0.555 = 0.2083
  • One red and one blue = 1 - 0.2777 - 0.2083 = 0.5138

Therefore, the probability of getting two red counters is 27.77%, the probability of getting two blue counters is 20.38%, and the probability of getting one of each color is 51.38%.

Learn more about probability in brainly.com/question/25638875

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