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nydimaria [60]
3 years ago
14

The half-life of chromium−51 is 27.8 days. How much of a 7.6−oz sample of chromium−51 will remain after 139 days?

Mathematics
1 answer:
In-s [12.5K]3 years ago
6 0
Ending Amount = Beginning Amount / 2^n
where "n" is the number of half-lives
n = 139 / 27.8 = 5 half-lives
Ending Amount = 7.6 oz / 2^5
Ending Amount = 7.6 oz / 32
Ending Amount = .2375 ounces

Source:
http://www.1728.org/halflife.htm


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2 1/7 :(1.5a)= 5/14 :0.8 PLEASE HELP NEED ANSWER BY TOMORROW
koban [17]

Value of a is 3.22

Step-by-step explanation:

Solving the given expression:

2\frac{1}{7}:(1.5a)=\frac{5}{14}:0.8

Solving and finding the value of a.

2\frac{1}{7}:(1.5a)=\frac{5}{14}:0.8\\\frac{15}{7}:(1.5a)= \frac{5}{14}:0.8\\Ratio\,\,can\,\, be\,\, written\,\, in\,\, fraction\,\, form:\\\frac{\frac{15}{7}}{1.5a}=\frac{\frac{5}{14}}{0.8}\\ Cross\,\,multiply:\\\frac{15}{7}*0.8=\frac{5}{14}*1.5a\\1.71=0.53\,\,a\\a= \frac{1.71}{0.53}\\a=3.22

So, value of a is 3.22

Keywords: Ratio

Learn more about Ratio at:

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