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Alla [95]
3 years ago
9

The population of a certain species of fish has a growth rate of 2.2% per year. It is estimated that the the current population

is 350,000. Estimate the number of years it will take the fish population to reach 1,000,000. Round your answer to the nearest tenth.
Mathematics
1 answer:
Darina [25.2K]3 years ago
4 0

We have been given that the population of a certain species of fish has a growth rate of 2.2% per year. It is estimated that the the current population is 350,000.

We are asked to find the time it will take the fish population to reach 1,000,000.

We will use exponential growth formula to solve our given problem.

An exponential growth function is in form y=a\cdot (1+r)^x, where,

y = Final amount,

a = Initial amount,

r = Growth rate in decimal form,

x = Time

2.2\%=\frac{2.2}{100}=0.022

y=350,000\cdot (1+0.022)^x

To find the time for the fish population to reach 1,000,000, we will substitute x=1,000,000 in our equation as:

1,000,000=350,000\cdot (1+0.022)^x

1,000,000=350,000\cdot (1.022)^x

\frac{1,000,000}{350,000}=\frac{350,000\cdot (1.022)^x}{350,000}

2.8571428571428571=(1.022)^x

Now we will take natural log on both sides:

\text{ln}(2.8571428571428571)=\text{ln}((1.022)^x)

\text{ln}(2.8571428571428571)=x\cdot \text{ln}(1.022)

x=\frac{\text{ln}(2.8571428571428571)}{\text{ln}(1.022)}

x=\frac{1.0498221244986776733}{0.0217614917815127}

x=48.2421947

Upon rounding to nearest tenth, we will get:

x\approx 48.2

Therefore, it will take approximately 48.2 years for the fish population to reach 1,000,000.

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jok3333 [9.3K]

Answer:

The value of the test statistic = 2.58

Test statistic Z = - 4.805

|Z| = 4.805 > 2.58

Null hypothesis is rejected The value of the test statistic = 2.58

There is  significant difference between in the mean number of times men and women send a Twitter message in a day

Step-by-step explanation:

Step(i):-

Sample size of men  n₁ = 25

mean of the first sample x₁⁻ = 20

Standard deviation of the first sample σ₁ = 5

Sample size of women n₂ = 30

mean of the second sample x₂⁻ = 30

Standard deviation of the first sample σ₂ = 10

Level of significance ∝= 0.01

<u>Step(ii)</u>:-

Null Hypothesis : H₀: There is no significant difference between in the mean number of times men and women send a Twitter message in a day

Alternative Hypothesis :H₁:There is  significant difference between in the mean number of times men and women send a Twitter message in a day

Test statistic

Z = \frac{x^{-} _{1} - x^{-} _{2} }{\sqrt{\frac{S.D_{1} ^{2} }{n_{1} }+\frac{ S.D_{2} ^{2}}{n_{2} }  } }

Z = \frac{20 - 30 }{\sqrt{\frac{(5)^{2}  }{25 }+\frac{ (10)^{2}  }{ 30}  } }

Z =  \frac{-10}{2.081} = - 4.805

The value of the test statistic = 2.58 C

|Z| = 4.805 > 2.58

Null hypothesis is rejected The value of the test statistic = 2.58

<u>Conclusion:</u>-

There is  significant difference between in the mean number of times men and women send a Twitter message in a day

7 0
3 years ago
The height of an overhand volleyball serve can be modeled as h=-16t^2+20t+6. After how many seconds is the ball 11 feet.
Andrew [12]

Answer:

0.9043secs and 0.3456secs

Step-by-step explanation:

Given the height of an overhand volleyball modeled as h=-16t^2+20t+6.

If the height is 11feet, then;

11 = -16t^2+20t+6.

-16t^2+20t+6 - 11 = 0

-16t^2+20t-5 = 0

Multiply thriugh by -1

16t^2-20t+5 = 0

Factorize

t = 20±√20²-4(16)(5)/2(16)

t = 20 ±√400-320/32

t = 20 ±√80/32

t = 20 ±4√5/32

t = 20±8.94/32

t = 28.94/32 and 11.06/32

t = 0.9043 and 0.3456

Hence the required time are 0.9043secs and 0.3456secs

8 0
3 years ago
What are the domain, range, and asymptote of h(x) = (0.5)x - 9
svetlana [45]

Answer:

The domain of h(x) is {x : x ∈ R}

The range of the function is {y : y > -9}

The horizontal asymptote is at y = -9

Step-by-step explanation:

* Lets read the problem and solve it

- The exponential function is f(x) = a(b)^x, where a and b are constant

  and b is the base , x is the exponent , a is the initial value of f(x)

- The domain of the function is all the values of x which make the

  function defined

- The range of the function is the set of values of y that corresponding

  with the domain x

- Asymptote on the graph a line which is approached by a curve but

 never reached

- A function of the form f(x) = a(b^x) + c always has a horizontal

 asymptote at y = c

* Lets solve the problem

∵ h(x) = (0.5)^x - 9

∵ All the values of x make h(x) defined

∵ The domain of the function is the values of x

∴ The domain of h(x) is {x : x ∈ R} ⇒ R is the set of real number

∵ The range of the function is the set of values of y which

   corresponding to x

∵ (0.5)^x must be positive because there is no values of x make it

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∴ y must be greater than -9

∴ The range of the function is {y : y > -9}

∵ A function of the form f(x) = a (bx) + c always has a horizontal

   asymptote at y = c

∵ h(x) = (0.5)^x - 9

∴ c = -9

∴ The horizontal asymptote is at y = -9

* Look to the attached file for more understanding

3 0
4 years ago
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Answer:

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3 0
2 years ago
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sladkih [1.3K]

M < 7 / 12

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(-5) < 7 / 12

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B C D maybe?

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