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katovenus [111]
3 years ago
8

I hope you guys can see the question, if not just let me know

Mathematics
1 answer:
QveST [7]3 years ago
3 0

Answer:

The correct answer is 6.

Step-by-step explanation:

When translating and reflecting figures, the shape remains the same. So, the side of 2x-4 is corresponding to the side of 8 and they are equal to each other.

To solve, set up an equation like this to find x:

2x-4=8

Then, add 4 to both sides of the equation:

2x=12

The goal is to get x by itself and in order to do that, divide both sides by 2:

x=6

The value of x is 6. I hope this helps! ☺

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70 POINTS! PLEASE HELP! Explain the difference between the following equation formats: Slope-Intercept, Point-Slope and Standard
katrin2010 [14]

Answer and Step-by-step explanation:

1.  slope intercept

2.  point-slope form

3.  standard

Explanation:

1.   A <u>slope intercept form</u> equation is when it's set up as y = m x + b

m = slope  

b = y-intercept

2.   <u>A point-slope form</u> is when a line passes through a point

and the equation is set up as  y −b = m ( x−a)

m = slope

(a, b) A point that the line passes through

3. <u>standard lope form</u> is when the equation is set up as

Ax + By = C

7 0
3 years ago
HELP ME PLEASE<br> RIGHT ANSWERS ONLYYY PLEASE
forsale [732]

The correct answer is

F. x = 8

8 0
3 years ago
Find an equation for the line perpendicular to y = − 1 /9 x + 4 with x-intercept at x = -1
prisoha [69]
Y = (-1/9).x + 4
The slope m of the line perpendicular to y = (-1/9).x + 4 is equal to 9:
(if the product of 2 slopes = - 1, then the 2 lines are perpendicular)

y = 9x + b, Since it passes by the point (-1,0) , then:
 0= 9(-1) + b and b = 9
Final equation:

y = 9x+9
 
6 0
3 years ago
Help 6th grade math i will give brainliest
eimsori [14]
<h2>Answer:</h2><h2>ADD 53+1 </h2>

Step-by-step explanation:

plz give brainlyest

4* 53+1/(8-5)^3

4(54)/(8−5)3

4(54/3^3)

4(54/27)

(4)(2)=8  the answer is 8

5 0
2 years ago
Read 2 more answers
Pls help I really need the answer right now​
Step2247 [10]
Use photo-math or Gauth-math application can help u this
5 0
2 years ago
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