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2 years ago

3 months ago Santos could walk 2 miles in 40 min. today he can walk 2 miles in 25 min. find percent of change

Mathematics

1 answer:

uranmaximum [27]2 years ago

8 0

The percentage of change is -37.5%

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Use the Remainder Theorem to find the remainder for (4x^3+4x^2+2x+3)/(x-1) and state whether or not the binomial is a factor of

Gnesinka [82]

Answer:

The remainder = 13.

Step-by-step explanation:

By the Remainder Theorem the remainder when the function is divided by

x - 1 is f(1).

f(1) = 4(1)^3 + 4(1)^2 + 2(1) + 3

= 4 + 4 + 2 + 3

= 13.

So x - 1 is not a factor of f(x).

If it was a factor the remainder would be 0.

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Stacy and Neil painted 280 ft of their living room wall with 4/5 gallon of paint. How many square feet can they paint with 3 gal

barxatty [35]

Step-by-step explanation:

4/5 gallons for 280 ft² (the ² is missing in the question ...).

3 gallons would be 15/5.

so, what do I need to multiply 4 with to get 15 ?

4×x = 15

x = 15/4

multiplying now also 280 ft² with this factor gives us the answer :

280 × 15/4 = 70 × 15 = 1050 ft²

they can paint 1050 ft² with 3 gallons of paint.

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2 years ago

jamil always throws loose change into a pencil holder on his desk and takes it out every two weeks. this time it is all nickels

valentinak56 [21]

Answer:

20.6

Step-by-step explanation:

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3 years ago

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Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)

Crazy boy [7]

Answer:

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Step-by-step explanation:

To find : Convert $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}$ into $\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Solution :

We convert units one by one,

$1\text{ m}^2=10.7639\text{ ft}^2$

$1\text{ sec}=\frac{1}{3600}\text{ hour}$

$1\text{ cal}=0.003968\text{ BTU}$

Converting temperature unit,

$^\circ C\times \frac{9}{5}+32=^\circ F$

$1^\circ C\times \frac{9}{5}+32=33.8^\circ F$

So, $1^\circ C=33.8^\circ F$

Substitute all the values in the unit conversion,

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Therefore, The conversion of unit is $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

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