Answer:
i don't now
Step-by-step explanation:
Answer:
c. 9 det A
Step-by-step explanation:
Given the following data;
Since A is a square matrix of order 2, we know that n = 2
K = 3
For any scalar k;
∣kA∣ = k^{n} ∣A∣
<em>Substituting into the equation;</em>
∣-3A∣ = -3²∣A∣
Simplifying, we have;
∣-3A∣ = 9∣A∣
= 9 detA
<em>Therefore, det (-3A) = 9 detA</em>
I think u should check the first one again u made a mistake but the second one is correct if u need any more help ask me
Answer:
Step-by-step explanation:
1 ) 2 + 7t [ there are no like terms , so no further simplifying ]
2) 6r + ( - 16 r )
= 6 r - 16 r [ both are like terms ]
= - 10 r
3) (3x + 2 ) + ( 2x - 4 )
= 3x + 2 + 2x - 4
= 3x + 2x - 4 + 2 [ arranging like terms together ]
= 5x - 2
4) (8 n² - 3 n + 6 ) + ( n - 2 )
= 8n² - 3n + 6 + n - 2
= 8n² - 3n + n + 6 - 2 [ bringing like terms together ]
= 8n² - 2n + 4
