Question

Find the equation for the linear function that passes through the points (-4,-2)and(4,0)Answers must use whole numbers and/or fractions, not decimals

Answer 1

Answer:

$y=-\frac{1}{4} x+1$

Step-by-step explanation:

Since they give you two points on the lane (-4,2) and (4,0), the line can be determined by using them to find:

1) the slope of the line via the formula:

$slope=\frac{y_2-y_1}{x_2-x_1} =\frac{(0-2)}{4--4} =\frac{-2}{8} =-\frac{1}{4}$

2) the line's y-intercept (b) requiring that one of the points satisfies the general equation of the line with the slope found above:

$y=m\,x+b\\y=-\frac{1}{4} x+b$

For example using point (4,0) in the equation above:

$y=-\frac{1}{4} x+b\\0=-\frac{1}{4} (4)+b\\0=-1+b\\1=b$

So the equation of the line through those points in slope intercept form is:

$y=-\frac{1}{4} x+1$