Answer:
D
Step-by-step explanation:
Answer:
a)
b)
c) P(X=6)=0
d) P(X=9)=0
Step-by-step explanation:
We know that are 4 men and 6 women are ranked according to their scores on an exam. X = 1 indicates that a man achieved the highest score on the exam.
a) We calculate P(X=2).
We calculate the number of possible combinations
We calculate the number of favorable combinations
We get that is
b) We calculate P(X=3).
We calculate the number of possible combinations
We calculate the number of favorable combinations
We get that is
c) We calculate P(X=6). This case is not possible because 6 men cannot be selected because we have been given 4 men.
We conclude P(X=6)=0.
d) We calculate P(X=9). This case is not possible because 9 men cannot be selected because we have been given 4 men.
We conclude P(X=9)=0.
Unfortunately I can not help you
Since 64/3 = 21 + 1/3 > 21, I assume <em>S</em> is supposed to be the value of the infinite sum. So we have for some constants <em>a</em> and <em>r</em> (where |<em>r</em> | < 1),
Consider the <em>k</em>-th partial sum of the series,
Multiply both sides by <em>r</em> :
Subtract this from :
Now as <em>k</em> goes to ∞, the <em>r ᵏ</em> term converges to 0, which leaves us with
which we can solve for <em>a</em> :
Meanwhile, the 3rd partial sum is given to be
Substitute <em>a</em> into this equation and solve for <em>r</em> :
Now solve for <em>a</em> :
It follows that