Answer:
Solution: x = 2, y = -1 or (2, -1)
Step-by-step explanation:
Equation 1: 2x + y = 3
Equation 2: 5x - 2y = 12
Using the substitution method:
Transform the Equation 1 into its slope-intercept form:
2x + y = 3
2x - 2x + y = -2x + 3
y = 2x + 3
Substitute the value of y = -2x + 3 into Equation 2:
5x - 2y = 12
5x - 2(-2x + 3) = 12
5x + 4x - 6 = 12
9x - 6 = 12
9x - 6 + 6 = 12 + 6
9x = 18
9x/9 = 18/9
x = 2
Substitute the value of x = 2 into Equation 2 to solve for y:
5x - 2y = 12
5(2) - 2y = 12
10 - 2y = 12
10 - 10 - 2y = 12 - 10
-2y = 2
-2y/-2 = 2/-2
y = -1
Double-check whether the values for x and y will provide a true statement for both equations:
Equation 1: 2x + y = 3
2(2) + (-1) = 3
4 - 1 = 3
3 = 3 (True statement)
Equation 2: 5x - 2y = 12
5(2) - 2(-1) = 12
10 + 2 = 12
12 = 12 (True statement)
Therefore, the correct answers are: x = 2; y = -1 or (2, -1).
Answer:
Step-by-step explanation:
A
Answer:
a= k/4+9b
Step-by-step explanation:
hope this helps, if not let me know!
Answer:
I am pretty sure it is when you have a sequence of numbers that you are subtracting or adding from by the same constant over and over
Step-by-step explanation:
an=a1+(n-1)d
d=common difference
an= the nth term in the sequence
a1 first term in the sequence. (Usually you can plug in 1, as the n, and work from there)
