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Ray Of Light [21]
3 years ago
10

Billie solved the equation below by completing the square, but she got the incorrect solution. In which step did Billie first ma

ke an error? Choices: 1234
Step 1: x^2+10x=49

Step 2: x^2+10x+25=49

Step 3: (x+5)^2=49

Step 4: x+5=+-7

Step 5: x=2, x=–12
Mathematics
1 answer:
Tanzania [10]3 years ago
5 0

Answer:

step 2

Step-by-step explanation:

we have

x^{2} +10x-49=0 ---> given problem

step 1

Move the constant to the right side

x^{2} +10x=49

the step 1 is correct

step 2

Complete the square

x^{2} +10x+5^2=49+5^2

x^{2} +10x+5^2=74

<u><em>The step 2 is not correct</em></u>

step 3

Rewrite as perfect squares

(x+5)^{2}=74

step 4

take square root both sides

x+5=\pm\sqrt{74}

step 5

Find the values of x

x=-5\pm\sqrt{74}

x=-5+\sqrt{74}

x=-5-\sqrt{74}

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Answer:

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Step-by-step explanation:

1.

Simplify the expression by combining like terms. Remember, like terms have the same variable part, to simplify these terms, one performs operations between the coefficients. Please note that a variable with an exponent is not the same as a variable without the exponent. A term with no variable part is referred to as a constant, constants are like terms.

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Use a very similar method to solve this problem as used in the first. Please note that all of the rules mentioned in the first problem also apply to this problem; for that matter, the rules mentioned in the first problem generally apply to any pre-algebra problem.

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Use the same rules as applied in the first problem. Also, keep the distributive property in mind. In simple terms, the distributive property states the following (a(b+c)=(a)(b)+(a)(c)=ab+ac). Also note, a term raised to an exponent is equal to the term times itself the number of times the exponent indicates. In the event that the term raised to an exponent is a constant, one can simplify it. Apply these properties here,

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3 years ago
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Answer:

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