Answer:

Step-by-step explanation:
1.
Simplify the expression by combining like terms. Remember, like terms have the same variable part, to simplify these terms, one performs operations between the coefficients. Please note that a variable with an exponent is not the same as a variable without the exponent. A term with no variable part is referred to as a constant, constants are like terms.



2.
Use a very similar method to solve this problem as used in the first. Please note that all of the rules mentioned in the first problem also apply to this problem; for that matter, the rules mentioned in the first problem generally apply to any pre-algebra problem.



3.
Use the same rules as applied in the first problem. Also, keep the distributive property in mind. In simple terms, the distributive property states the following (
). Also note, a term raised to an exponent is equal to the term times itself the number of times the exponent indicates. In the event that the term raised to an exponent is a constant, one can simplify it. Apply these properties here,







4.
The same method used to solve problem (3) can be applied to this problem.






Is probably C and D good luck!
And have a nice day
Answer:
D. 16 Cars; 35 Motorcycles
Step-by-step explanation:
16*4= 64 Multiply the number of cars by the number of wheels a car has
35*2= 70 Multiply the number of Motorcyles by the number of wheels a Motorcycle has
Then add them---> 64+70= 134
Answer:
Step-by-step explanation:
Given that 97 cities were surveyed to determine sports teams. 25 had soccer, 24 had rugy, 21 had basketball, 12 had soccer and rugby, 11 had soccer and basketball, 12 had rugby and basketball, and 5 had all three.
a) Only rugy team =5
b) Soccer and rugby but not basket ball = 7(green shaded in the diagram)
c) Soccer or rugy = 25+24-12= 37
d) soccer or rugby, but not basketball=37-(6+5+7) = 19
e) Exactly two teams = 7=7+6 = 20
f) Atleast two teams = 7+5+6+7 =25
g) Atleast one team = Total - no team = 40
h) No teams = 91-40 = 51
Answer:
it depends on the weight on the assignment or test but you will probably be at a 68-71
Step-by-step explanation: