Consecutive integers area 1 apart
they are
x,x+1,x+2
sum is
x+x+1+x+2=87
3x+3=87
minus 3 both sides
3x=84
divide both sides by 3
x=28
x+1=29
x+2=30
the smallest number is 28
Hello,
Let's assume a,b,c the 3 numbers
a+b+c=62
b=a-4
c=4*a
==>a+(a-4)+4a=62
==>6a=66
==>a=11
b=11-4=7
c=4*11=44
The 3 numbers are 11;7;44
Proofs:
11+7+44=62
7=11-4
44=4*11
Answer:
C, D, E
Step-by-step explanation:
C: simplify the expression
D: rewriting the expression
E: use distributive property to simplify
0.524 is the correct answer (✿^‿^)
