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Ostrovityanka [42]
3 years ago
13

What is the value of 12^0​

Mathematics
2 answers:
grigory [225]3 years ago
7 0

Answer:

1

Step-by-step explanation:

SCORPION-xisa [38]3 years ago
6 0
The answer to your question is 1
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Find the complex fourth roots \[-\sqrt{3}+\iota \] in polar form.
____ [38]

Let z=-\sqrt3+i. Then

|z|=\sqrt{(-\sqrt3)^2+1^2}=2

z lies in the second quadrant, so

\arg z=\pi+\tan^{-1}\left(-\dfrac1{\sqrt3}\right)=\dfrac{5\pi}6

So we have

z=2e^{i5\pi/6}

and the fourth roots of z are

2^{1/4}e^{i(5\pi/6+k\pi)/4}

where k\in\{0,1,2,3\}. In particular, they are

2^{1/4}e^{i(5\pi/6)/4}=2^{1/4}e^{i5\pi/24}

2^{1/4}e^{i(5\pi/6+2\pi)/4}=2^{1/4}e^{i17\pi/24}

2^{1/4}e^{i(5\pi/6+4\pi)/4}=2^{1/4}e^{i29\pi/24}

2^{1/4}e^{i(5\pi/6+6\pi)/4}=2^{1/4}e^{i41\pi/24}

7 0
3 years ago
Solve: -2/3a - 6 = 12 <br>a =​
Anika [276]

Answer: -27 is the correct answer. (apparently)

7 0
3 years ago
Need help fast don't understand both A and B show work please
Shkiper50 [21]
Problem A
Usually the number of bits in a byte is 8 or 16 or 32 and recently 64. You don't have to write a formula to restrict it to this number of bits. You are not asked to do so. The general formula is 2^n - 1 for the problem of Millie and her golden keys. Somehow the system can be made to choose the right number of bits. Apple IIe s for example, used 8 bits and there was a location that told the processor that fact.

2^n - 1 <<<<< Answer

Problem B
In this case n = 4
2^n - 1 = 2^4 - 1 = 16 - 1 = 15


Millie can collect 15 keys <<<<<< Answer
5 0
3 years ago
Ali scored 58 marks in eng and 49 in math . how much percent in eng more than math​
Sergeu [11.5K]

Answer: 9%

Step-by-step explanation: as all the marks are out of 100 i suppose

so Ali got 58% at eng and 49% at math

so 58-49=9%

and that is how we get the answer

4 0
3 years ago
Read 2 more answers
The Delucci family traveled on the highway for two hours at 70 miles per hour, and then three hours at 35 miles per hour. How fa
Zinaida [17]
(2 * 70) + (3 * 35) = 140 + 105 = 245 miles
6 0
4 years ago
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