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3 years ago

CAN SOMEONE PLEASE CHECK IF I DID THIS CORRECT??? PLEASE JUST ANSWER ASAP FOR BRAINLIEST!!!

Mathematics

1 answer:

Serga [27]3 years ago

8 0

Answer:

Step-by-step explanation:

The top dot is the vertex, and it goes on point (3,4)

Also the right dot goes over 5 and not 4, the x of the vertex will always be the average of the two roots

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How do I find the area ?

zalisa [80]

Answer:

7.74 cm^2

Step-by-step explanation:

The length of the side of the square is 3+3 = 6

The area of the square is

A =s^2 = 6^2 = 36

The area of the circle is

A = pi r^2 where the radius is 3

(3.14) 3^2 =28.26

Subtract the area of the circle from the area of the square to get the shaded area

36-28.26 = 7.74 cm^2

5 0

3 years ago

If f(x)=-5 find the value of x

Greeley [361]

f(x) is a fancy way to say y

The equation says y=05, so x is ungiven based on what you have given us. Please check if there was more information written as usually its written as

Example: f(x)=3x+5

5 0

2 years ago

Please do provide a correct answer because other ways I will report/block you. Please be honest and help me, please.

Irina-Kira [14]

Answer:

incomplete

Step-by-step explanation:

please send the full information, I can't see students belonging to acers

4 0

2 years ago

A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co

Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let $\mu$ = mean weight of coffee in its containers.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 32 ounces {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, $H_A$ : $\mu$ < 32 ounces {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = 31.8 ounces

s = sample standard deviation = 0.48 ounces

n = sample of containers = 15

So, the test statistics = $\frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }$ ~ $t_1_4$

= -1.614

The value of t test statistics is -1.614.

Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0

3 years ago

The graph of the piecewise function f(x) is shown what is the domain of f(x)

Rom4ik [11]

The domain of a function is where we have a value for x.

Since that's the case the domain of f(x) = {x e R / 1 ≤ x < 5}

We see that we have a value for x = 1 cuz we have a filled circle, but we don't have a value for x = 5, look at the unfilled circle

So, our x can vary between 1 and 5, but can't be 5.

8 0

3 years ago