Answer:
10 ways
Step-by-step explanation:
The number of ways in which five basketball players could be placed in three positions is:
5
= 
= 
= 
= 5 × 2
= 10
The basketball players can be arranged in 10 ways.
Answer:

Step-by-step explanation:
add the distribution property, then add 30 then - 14x then divide by 11
i) The given function is

The domain is



ii) For vertical asymptotes, we simplify the function to get;

The vertical asymptote occurs at


iii) The roots are the x-intercepts of the reduced fraction.
Equate the numerator of the reduced fraction to zero.



iv) To find the y-intercept, we substitute
into the reduced fraction.



v) The horizontal asymptote is given by;

The horizontal asymptote is
.
vi) The function has a hole at
.
Thus at
.
This is the factor common to both the numerator and the denominator.
vii) The function is a proper rational function.
Proper rational functions do not have oblique asymptotes.
Well 3.20 is 2 tenths of 1 and .02 is 2 hundredths of one so its >
Answer:
1,2,3,4,5
Step-by-step explanation:
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