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Salsk061 [2.6K]
3 years ago
11

How many solutions does the equation have?

Mathematics
1 answer:
son4ous [18]3 years ago
3 0
The equation would have infinite solutions.
First, distribute on both sides, and you get 12x - 6 = 12x - 6.
There are two ways to do this from here. first is: you add six to both sides and they'll cancel out, and you'll have 12x = 12x. Then you divide by 12 on both sides and get x = x.  When the two sides equal the same thing, there are infinite solutions.
Or, we can do the easy way. As you can see, 12x-6 = 12x-6. Both the sides are clearly the same, so we actually don't need to do the rest.
ANSWER: infinite solutions
Hope this helped!!(:
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2) 131.8
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4) 88.5
5) 90.3
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Explanation:
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The diagonals of a rhombus have lengths of 12 centimeters and 16 centimeters. what is the length of one side of the rhombus
Yuki888 [10]
<span>Diagonals of a rhombus are perpendicular and bisect each other. This means this rhombus is composed of four right triangles with legs of length 6 cm and 8 cm, with their hypotenuses forming the perimeter of the rhombus. The Pythagorean theorem a^2+ b^2 = c^2 can be used to find the length of the hypotenuse. 6^2+8^2 = 36+64 = 100. The square root of 100 is 10, so the length of a side of the rhombus is 10 cm.</span>
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5 0
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PLEASE HELP ASAP. RIGHT ANSWER WILL GET BRAINLIEST
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Given
P(1,-3); P'(-3,1)
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(x,y)->(y,x)  which corresponds to a single reflection about the line y=x.
Alternatively, the same result may be obtained by first reflecting about the x-axis, then a positive (clockwise) rotation of 90 degrees, as follows:
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4 0
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Read 2 more answers
A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D.
yKpoI14uk [10]

The correct statement is:

  • There are four ways to choose the committee.
  • There are three ways to form the committee if person D must be on it.
  • If persons B and C must be on the committee, there are two ways to form the committee.

It is given that:

A membership committee of three is formed from four eligible members.

1) There are four ways to choose the committee.

This statement is true.

Since we have to choose 3 members out of the 4 members so we can use the method of combination.

2) There are three ways to form the committee if person D must be on it.

This statement is also true.

Since D has to be in the committee, this means we have to choose 2 more people out of the three people to form the committee.

3) If seven members are eligible next year, then there will be fewer combinations.

This statement is wrong.

Since we have to choose 3 members out of 7 members so the number of possible combinations will be:

There are 35 combinations possible.

4) If persons B and C must be on the committee, there are two ways to form the committee.

If B and C have to be in the committee then we have to choose just one person out of the two people left.

Hence, the statement is true.

5) If persons A and C must be on the committee, then there is only one way to form the committee.

If A and C have to be on the committee then as in the last option we have to choose any one of the two-person left.

So possible number of ways is 2.

Hence, the statement is false.

Learn more about committee here: brainly.com/question/425830

#SPJ4

<em>Your question is incomplete. Please read below to find the missing content.</em>

<em />

A membership committee of three is formed from four eligible members. Let the eligible members be represented by A, B, C, and D. The possible outcomes include S = {ABC, ABD, ACD, BCD}.

Which statements about the situation are true? Check all that apply.

There are four ways to choose the committee.

There are three ways to form the committee if person D must be on it.

If seven members are eligible next year, then there will be fewer combinations.

If persons B and C must be on the committee, there are two ways to form the committee.

If persons A and C must be on the committee, then there is only one way to form the committee.

8 0
2 years ago
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