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Reika [66]
3 years ago
7

Eckhart school is selling candy to raise money for its sports programs . Last year the school raised $480 during a 12 day fundra

iser. The expects this years daily sales to be in proportion to last years daily sales . Based on the schools expectations ,which of the following statement is true ?
Mathematics
2 answers:
Galina-37 [17]3 years ago
8 0

Answer:

120

Step-by-step explanation:

:)

Ber [7]3 years ago
3 0

Answer:

answer my question

Step-by-step explanation:

help pls!!!!!

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The lines graphed below are perpendicular. The slope of the red line is -2.
ASHA 777 [7]

Answer:

1/2

Step-by-step explanation:

opposite reciprocal

4 0
3 years ago
First, I add 1. Then, I multiply by 2. Next, I divide by 3. As a result, I get 4. What is my starting number?
Ira Lisetskai [31]

Answer:5

Step-by-step explanation:

reverse the steps

2(x+1)/3=4

2(x+1)/3×3=4×3

2(x+1)/2=12/2

x+1=6

x=6-1

x=5

6 0
3 years ago
Read 2 more answers
Name two decimals whose sum is less then 1
harina [27]

0.1 0.2 because its only sum of only 0.3

5 0
3 years ago
Find the common ratio for the following sequence .1, .01, .001
morpeh [17]

Answer:

0.1

Step-by-step explanation:

The <em>common ratio</em> of a sequence is the number you multiply one term to get the next one. Here, we multiply 0.1 by 0.1 to get 0.01, and 0.01 by 0.1 to get 0.001, so our common ratio is 0.1.

5 0
3 years ago
Martha is late for class, so she races her 75 kg body up a 4.0 meter flight of stairs in only 2.3 seconds. What is Martha’s powe
vovangra [49]

Answer:

1.3\cdot 10^3\text{ J}

Step-by-step explanation:

Power is defined by work over time. In physics, work can be defined as the energy transferred over from an applied force over some distance. As a formula:

W=Fd, where F = force applied and d = distance that force is applied over.

*It is worth noting that F must be parallel to the distance travelled. If it is perpendicular, no work is done, and if it is at an angle, find the parallel component and use that for F.

In this case, the force applied must counter the force of gravity on Martha, which is given by F_g=mg, where m = Martha's mass and g = gravitational constant 9.8 m/s/s. Therefore, F_g=75\cdot 9.8=735\text{ N}. Since she raises her body 4.0 meters, the work done must be W=Fd=735\cdot 4=2940\text{ J}.

Since power is equal to work over time and t = 2.3 seconds, we have:

\displaystyle P=\frac{W}{t}=\frac{2940}{2.3}=\boxed{1278\text{ J}}\approx \boxed{1.3\cdot 10^3\text{ J}} (to two significant figures)

7 0
2 years ago
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