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3 years ago

What is the solution to 5(34+12)/2?

Mathematics

2 answers:

Firlakuza [10]3 years ago

7 0

The answer is 115. ;)

tresset_1 [31]3 years ago

3 0

The answer would be the sum of 34 and 12 times 5 then /2. That = 115.

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The weight of a bull clad is 388 kilograms. If it’s weight increases at a rate of 1 2/5 kilograms per day how long it will take

Alex73 [517]

Answer:

It will take 80 days for the bull calf to reach a weight of 500 kilograms.

Step-by-step explanation:

Given:

The weight of a bull calf is 388 kilograms.

Now, to find the weight of bull calf of how long it will take to reach a weight of 500 kilograms, if it’s weight increases at a rate of 1 2/5 kilograms per day.

Required weight which to be increased = 500 - 388 = 112 kilograms.

Rate of weight increase = $1\frac{2}{5}=\frac{7}{5}$

= $1.4\ kilograms.$

Thus, the time required = $\frac{required\ weight}{rate\ of\ weight}$

= $\frac{112}{1.4}$

= $80.$

The time required = 80 days.

Therefore, it will take 80 days for the bull calf to reach a weight of 500 kilograms.

5 0

3 years ago

A force (F) applied to an object of mass m1 produces an acceleration of 3.00 m/s^2.

Lerok [7]

A) For object with mass m1,
F = m1 * 3
m1 = F/3

For object with mass m2,
F = m2 * 1
m2 = F

Ratio of m1/m2
(F/3) / F = 1/3

6 0

3 years ago

Read 2 more answers

How long will it take for an investment to triple if it is compounded continuously at 12%

myrzilka [38]

Answer:

9.694 years

Step-by-step explanation:

Let the investment is $P.

So, we are asked to determine the time it will grow to triple with the compound interest rate of 12%.

Let the time is y years.

So, from the formula of compound interest we can write

$3P = P(1 + \frac{12}{100} )^{y}$

⇒ $(1 + \frac{12}{100} )^{y} = 3$

⇒ $(1.12)^{y} = 3$

Now, taking log both sides we get,

y log 1.12 = log 3 {Since, $\log a^{b} = b \log a$ }

⇒ 0.04922y = 0.477712

⇒ y = 9.694 years (Answer)

3 0

3 years ago

2x^2+5x+3/x^2-3x-4 divided by 4x^2+2x-6/x^2-8x+16

Masja [62]

Answer: $\frac{x-4}{2x-2}$

Step-by-step explanation:

$\frac{2x^2+5x+3}{x^2-3x-4}$ divided by $\frac{4x^2+2x-6}{x^2-8x+16}$ is the same thing as multiplying $\frac{2x^2+5x+3}{x^2-3x-4}$ by $\frac{x^2-8x+16}{4x^2+2x-6}$ .