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gladu [14]
3 years ago
9

Locate 11/3 on a number line

Mathematics
2 answers:
geniusboy [140]3 years ago
4 0
11/3 would be closlely to 3.5 because it is 3.66667
zhuklara [117]3 years ago
3 0
Draw a number line with three notches for each number.

1      2       3       4       5
l--l--l--l--l--l--l--l--l--l--l--l--l

11/3 is equal to 3 2/3, so it would be two notches past 3, on the notch indicated with arrows below.


1      2       3    ↓ 4       5
l--l--l--l--l--l--l--l--l--l--l--l--l
                      ↑

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please help!! 20 points if u just comment to take my points or guess i’ll make sure ur account gets banned. thank you!!
LekaFEV [45]

Answer:

I believe it's A and B

Step-by-step explanation:

3 0
2 years ago
The average amount of water in randomly selected 16-ounce bottles of water is 16.15 ounces with a standard deviation of 0.45 oun
vekshin1

Answer:

0.0179 = 1.79% probability that the mean of this sample is less than 15.99 ounces of water.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 16.15, \sigma = 0.45, n = 35, s = \frac{0.45}{\sqrt{35}} = 0.0761

What is the probability that the mean of this sample is less than 15.99 ounces of water?

This is the pvalue of Z when X = 15.99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{15.99 - 16.15}{0.0761}

Z = -2.1

Z = -2.1 has a pvalue of 0.0179

0.0179 = 1.79% probability that the mean of this sample is less than 15.99 ounces of water.

3 0
2 years ago
Quality control studies for Speedy Jet Computer Printers show the lifetime of the printer follows a normal distribution with mea
Anika [276]

Answer:

About 3 years Speedy Jet printers be guaranteed.

Step-by-step explanation:

Given : Quality control studies for Speedy Jet Computer Printers show the lifetime of the printer follows a normal distribution with

mean \mu = 4 and standard deviation  \sigma = 0.78

If the company wishes to replace no more than 10% of the printers.

To find : How long should Speedy Jet printers be guaranteed ?

Solution :

Using Z- table,  

Z value corresponding to 10% or 0.10 = -1.28.

Applying z-score formula,

z=\frac{x-\mu}{\sigma}

The value of x is given by,

x=(z\times \sigma)+\mu

Substitute the values,

x=(-1.28\times 0.78)+4

x=-0.9984+4

x=3.0016

So, approx 3 years.

Therefore, About 3 years Speedy Jet printers be guaranteed.

8 0
2 years ago
The formula for a trapezoid relates the area A, the two bases, a and b, and the height, h. A=(a+b)/2 h Solve for a.
yKpoI14uk [10]

Answer:

a=\frac{2A}{h}-b

Step-by-step explanation:

Hello, I think I can help you with this.

According to the information provided in the problem, the area of ​​a trapezoid is given by

A=\frac{a+b}{2} *h\\

Step 1

solve for a, it means isolate a

A=\frac{a+b}{2} *h\\divide\ both\ sides\ by\ h\\\\\frac{A}{h}= \frac{\frac{a+b}{2} *h}{h} \\\frac{A}{h}=\frac{a+b}{2}\\\\Now, multiply\ both\ sides\ by\ two\\\\ 2*\frac{A}{h}=2*\frac{a+b}{2}\\2*\frac{A}{h}=a+b\\\frac{2A}{h}=a+b\\\\subtract\ b\ for\ both\ sides\\\frac{2A}{h}-b=a+b-b\\a=\frac{2A}{h}-b

Have a good day.

5 0
3 years ago
A fair die is rolled repeatedly. find the expected number of rolls until all 6 faces appear.
Makovka662 [10]
Each face has a chance of 1/6
So you beed 6 rolls
8 0
3 years ago
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