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Alex73 [517]
3 years ago
13

The average amount of water in randomly selected 16-ounce bottles of water is 16.15 ounces with a standard deviation of 0.45 oun

ces. If a random sample of thirty-five 16-ounce bottles of water are selected, what is the probability that the mean of this sample is less than 15.99 ounces of water? Answer: (round to 4 decimal places)
Mathematics
1 answer:
vekshin13 years ago
3 0

Answer:

0.0179 = 1.79% probability that the mean of this sample is less than 15.99 ounces of water.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 16.15, \sigma = 0.45, n = 35, s = \frac{0.45}{\sqrt{35}} = 0.0761

What is the probability that the mean of this sample is less than 15.99 ounces of water?

This is the pvalue of Z when X = 15.99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{15.99 - 16.15}{0.0761}

Z = -2.1

Z = -2.1 has a pvalue of 0.0179

0.0179 = 1.79% probability that the mean of this sample is less than 15.99 ounces of water.

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In ABC, O is the centroid of the triangle and AO is 12.7 m. Find the length of OY and AY.​
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Answer:

\boxed{OY = 6.35 m} \\\boxed{AY=19.05 m}

Step-by-step explanation:

The centroid of a triangle always cuts a triangle perfectly at 2/3.

What I mean by this is that the line that touches the tip of the triangle and touches the median of the base is cut into one third and its other part is cut into two thirds of the whole segment. This segment is AY.

Knowing this, I can tell that OY is 1/3 of the length of AO, which is given to be 12.7 m.

To find OY, make an equation where AO and OY add up to AY.

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The variable x represents the length of AY, and 1/3x represents the length of OY (because it is one-third of AY).

Solve the equation by subtracting 1/3x from both sides.

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Now we know the length of AY (x). To find the length of OY substitute this value of x into 1/3x, which represents OY.

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This gives us 6.35, which is the length of OY.

The final answers are:

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