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photoshop1234 [79]
4 years ago
11

To find out how fast a tree grows, you can measure its trunk. A giant red oak's diameter was 248 inches in 1965. The tree's diam

eter had grown to 251 inches in 2005. Find the average rate of change in the diameter of the tree per year.
Mathematics
1 answer:
professor190 [17]4 years ago
8 0
Any times you see the phrase: "Rate of Change", or even sometimes just the word "Rate" think slope. 

The word slope is just a fancy word that means the rate of change. 

Rate of Change is just a fancy phrase meaning how much does something change over some amount of time. 
So in this case our rate of change will have the units of inches per year. 

Let's get to the problem at hand! 
We'll need to find slope / the rate of change (the two are interchangeable with each other).
Let's go over the formula for slope:

m = (y2 - y1) / (x2 - x1) 

First we will need to label each of the "coordinated points (the two numbers that go together in a pair)" with either (x1,y1) or (x2,y2). 

A Giant Red Oak's diameter in 1965 was 248 inches. Keep in mind time is ALWAYS going to be X in rate of change problems (and most all problems for that matter).  

(1965,248) 
(X1,Y2)

(2005,251)
(X2,Y2)

Plug in the values into the equation!
m = (y2 - y1) / (x2 - x1)
m = (251 - 248) / (2005 - 1965) 
m = (3) / (40)

Type that into a calculator to get a decimal value over 1.
m = 0.075 inches per 1 year. 
Or... 

m = 0.075in / 1 year
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Solve using elimination x-2y=12 and 5x+3y=-44 <br> (4,8)<br> (-4,8)<br> (4,-8)<br> (-4,-8)
Leya [2.2K]

Answer:

(-4, -8)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients
  • Solving systems of equations using substitution/elimination

Step-by-step explanation:

<u>Step 1: Define Systems</u>

x - 2y = 12

5x + 3y = -44

<u>Step 2: Rewrite Systems</u>

x - 2y = 12

  1. [Multiplication Property of Equality] Multiply everything by -5:                  -5x + 10y = -60

<u>Step 3: Redefine Systems</u>

-5x + 10y = -60

5x + 3y = -44

<u>Step 4: Solve for </u><em><u>y</u></em>

<em>Elimination</em>

  1. Combine 2 equations:                                                                                   13y = -104
  2. [Division Property of Equality] Divide 13 on both sides:                              y = -8

<u>Step 5: Solve for </u><em><u>x</u></em>

  1. Define original equation:                                                                               x - 2y = 12
  2. Substitute in <em>y</em>:                                                                                                x - 2(-8) = 12
  3. Multiply:                                                                                                           x + 16 = 12
  4. [Subtraction Property of Equality] Subtract 16 on both sides:                      x = -4
6 0
3 years ago
F(1)=-12, f(n)=2f(n-1) <br> find first 4 terms
amid [387]
<h3>First four terms are:   -12, -24, -48, -96</h3>

============================================

Explanation:

The notation f(1) = -12 tells us that the first term is -12.

The equation f(n) = 2*f(n-1) indicates that we're multiplying the (n-1)th term by 2 to get the nth term. Basically we multiply each term by 2 to get the next term.

-12*2 = -24

-24*2 = -48

-48*2 = -96

So the first four terms are -12, -24, -48, -96.

-----------------------------------

Alternative Approach

f(1) = -12 .... first term

f(n) = 2*f(n-1) ... nth term recursive formula

f(2) = 2*f(2-1) ... plug in n = 2

f(2) = 2*f(1)

f(2) = 2*(-12) ... plug in f(1) = -12

f(2) = -24 ... second term

f(n) = 2*f(n-1) .... resetting for the next computation

f(3) = 2*f(3-1) ... plug in n = 3

f(3) = 2*f(2)

f(3) = 2*(-24)  ... plug in f(2) = -24

f(3) = -48 .... third term

f(n) = 2*f(n-1) ... one more reset

f(4) = 2*f(4-1) .... plug in n = 4

f(4) = 2*f(3)

f(4) = 2*(-48) ... plug in f(3) = -48

f(4) = -96 ... fourth term

We get the first four terms to be -12, -24, -48, -96, which was the same as earlier.

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3 years ago
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Answer:

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3 years ago
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Answer:

Bottom right

Explanation:

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