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joja [24]
3 years ago
13

Find the radius of a circle with a circumference of 62

Mathematics
2 answers:
shusha [124]3 years ago
3 0

Answer:

31

Step-by-step explanation:

the radius is half of the curcumference

so you would just divide 62 by 2

62÷2

Dmitriy789 [7]3 years ago
3 0
It would be around 9.87 because the formula for radius with a given for circumference is r=C/2π .
62/2 π
r=9.87.....
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Use the law of cosines to find the length of side C.
sergij07 [2.7K]

Answer:

\text{D. 36.64}

Step-by-step explanation:

The Law of Sines is given by \frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C} and works for any triangle.

Therefore, we have the proportion:

\frac{c}{\sin 41.5^{\circ}}=\frac{37}{\sin 42^{\circ}},\\\\c=\frac{37\sin 41.5^{\circ}}{\sin 42^{\circ}}=36.6399945706\approx \boxed{36.64}

8 0
3 years ago
PLEASE HELP QUICK! I’ll give brainleist!!!
Fudgin [204]

1. set up the equation which makes these shapes equal, 1/2(2(x+1)) = 1x

2. solve, x+1=x, 1=0

3. since this is impossible, there is no solution and zero answers

5 0
3 years ago
12x+7<−11 AND5x−8≥4012
Arte-miy333 [17]

Answer:

No solution

Step-by-step explanation:

Given: 12x+7 and  5x-8\geq 40

Solve both inequality separately.

12x+7              Subtraction property of inequality

12x

12x

x

x

and

5x-8\geq 40               Addition property of inequality

5x\geq 40+8

5x\geq 48

x\geq \dfrac{48}{5}

Hence, the solution of the compound inequality intersection of both solutions.

Please find attachment for number line solution.

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8 0
3 years ago
Read 2 more answers
Write the equation of the line that passes through the points (3,5) and (-1,1). Put
dangina [55]

Given:

A line passes through the two points (3,5) and (-1,1).

To find:

The equation of the line in fully reduced point-slope form.

Solution:

If a line passes through two points, then the point slope form of the line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

The line passes through the two points (3,5) and (-1,1). So, the point slope form of the line is

y-5=\dfrac{1-5}{-1-3}(x-3)

y-5=\dfrac{-4}{-4}(x-3)

y-5=1(x-3)

Therefore, the  point slope form of the line in fully reduced form is y-5=1(x-3), here 1 is the slope of the line.

6 0
3 years ago
What is the value of z in the equation 2z + 7 = -5?<br> a. -6<br> b. -1<br> c. 1<br> d. 6
Mekhanik [1.2K]
2z +7 = -5

2z = -5 -7

2z = -12

z= -12 /2

z= -6
4 0
3 years ago
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