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3 years ago

Eight subtracted from 4 times a number is equal to 4 less than 6 times the number.

Mathematics

1 answer:

butalik [34]3 years ago

5 0

$8-4 \cdot x=4-6\cdot x \\\\ 8-4x=4-6x \\\\ -4x+6x=4-8 \\\\ 2x=-4 \ \ \ |:2 \\\\ \boxed{x=-2}$

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Determining function values from a graph

professor190 [17]

Answer:

The y value of a point where a vertical line intersects a graph represents an output for that input x value. If we can draw any vertical line that intersects a graph more than once, then the graph does not define a function because that x value has more than one output.

6 0

3 years ago

The length of the rectangular basketball court is 44 feet more than the width. If the perimeter of the basketball court is 288 f

Temka [501]

Let's first say that L=W+44

and then remember that perimeter is P=2L+2W

replace the L with W+44

we then get P=2(W+44)+2W, now I'll solve it

P=2W+88+2W
P=4W+88

substitute 288 for P

288=4W+88
200=4W
50=W

so now we now how wide the court is. add 44 to find the length which gives you L=94

as always plug the numbers back into your perimeter equation to ensure L and W are correct

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3 years ago

What is the y-intercept of function f? A. 1 B. -1 C. -2 D. 5

shtirl [24]

Answer:

Step-by-step explanation:

The y intercept is when x =0

We need to use the second equation

-x+1 since -2 < 0 <3

0+1

The y intercept is 1

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3 years ago

Keith has 39 books in his library he brought several books at a yard sale over the weekend he now has 84 in his library how many

garri49 [273]

Subtract original amount from new amount:

84 - 39 = 45

He bought 45 books.

3 0

3 years ago

Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently

garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

$\small \sum_{i = 1}^{k} L_i= 2\pi$

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

$\small \sum_{i = 1}^{k} C_i.l = 2\pi$

where C(i) is a constant coefficient obviously between 0 and 1.

$\small \sum_{i = 1}^{k} C_i= 2\pi/l$

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

$\small L_{Exp} = \frac{2\pi}{k}$

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3 years ago