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3 years ago

What is the value of theta , if tan theta = -1/squareroot3

1 answer:

6 0

$\bf tan(\theta )=-\cfrac{1}{\sqrt{3}}\impliedby \textit{simply means }\implies \measuredangle \theta =tan^{-1}\left( -\frac{1}{\sqrt{3}} \right)$

make sure your calculator is in Degree mode, if you need the angle in degrees, or Radian mode if you need the radian.

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Choose the correct vertex for the following quadratic function.

frez [133]

Answer:

U (2,-1)

Step-by-step explanation:

if you replace x to 2, your answer will come out to be -1

7 0

2 years ago

Read 2 more answers

Rationalize the denominator.

mel-nik [20]

Answer:

7sqrt(15) - 5sqrt(6)

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Step-by-step explanation:

7 -sqrt(10)

-----------------------

3 sqrt(5) *sqrt(3)

7 -sqrt(10)

-----------------------

3 sqrt(15)

Multiply the top and bottom by sqrt(15)/ sqrt(15)

7 -sqrt(10) sqrt(15)

----------------------- * ------------

3 sqrt(15) sqrt(15)

(7 -sqrt(10))* sqrt(15)

-----------------------------------

3 *15

Distribute

7sqrt(15) - sqrt(150)

------------------------------

sqrt(ab) =sqrt(a) sqrt(b)

150 = 25*6

7sqrt(15) - sqrt(25)sqrt(6)

------------------------------

7sqrt(15) - 5sqrt(6)

------------------------------

3 0

3 years ago

Garrick's science class recycles old batteries at the TRECA recycling center. The center pays a fixed amount for each ounce of m

Mars2501 [29]

T = na

because, total equals to ounces of the material times the amount payed.

8 0

3 years ago

Read 2 more answers

Let p: x = 4

STatiana [176]

P → q

EXPLANATION

p → q is a symbol for a conditional statement, an if-then statement in which p is a hypothesis and q is a conclusion. The logical connector in a conditional statement is denoted by the symbol →.

The conditional is defined to be true unless a true hypothesis leads to a false conclusion.

6 0

3 years ago

Show all steps!!!

Lunna [17]

$-\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|-\frac{2}{3}-2^3-\frac{2}{3}\left|-\frac{1}{2}\right|^3$
$\frac{1}{3}\left|1\cdot \left(\frac{1}{2}\right)^2\right|=\frac{1}{12}$
$\frac{2}{3}\left|-\frac{1}{2}\right|^3=\frac{1}{12}$
$=-\frac{1}{12}-\frac{2}{3}-2^3-\frac{1}{12}$
$=-\frac{53}{6}$

4 0

3 years ago