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Evgen [1.6K]
3 years ago
9

What is the value of theta , if tan theta = -1/squareroot3

Mathematics
1 answer:
larisa86 [58]3 years ago
6 0
\bf tan(\theta )=-\cfrac{1}{\sqrt{3}}\impliedby \textit{simply means }\implies \measuredangle \theta =tan^{-1}\left( -\frac{1}{\sqrt{3}} \right)

make sure your calculator is in Degree mode, if you need the angle in degrees, or Radian mode if you need the radian.
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Explain how to use a graph of the function f(x) to<br> find f(3).
Oksanka [162]

To find the value of f(3) we need to follow the below steps :

Step 1 : First plot the graph of f(x)

Step 2 : We need to find f(3) or the function value at x = 3 therefore, in the graph locate the point (3,0)

Step 3 : Draw a line parallel to Y-axis passing through the point (3,0) .

Step 4 : Now there exists two cases :

If the drawn line do not intersect the graph of f(x), then no value of f(3) exists for the given function of x

If the drawn line intersects the graph, then the intersection point is marked and a line parallel to x - axis is drawn passing through that marked or intersection point. And the line where it intersects the y - axis is our required value of f(3).

If this is wrong than I guess I wasn't smart enough :)

4 0
2 years ago
Drag values to order them from least to greatest, with least at the top.
GenaCL600 [577]
To solve this problem you must apply the proccedure shown below:

 1- You must rewrite each value shown in the picture attached, in decimal form, as following:

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 2- Now, you can order the values from least to greatest:

 √99
 6π-6
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3 0
3 years ago
Read 2 more answers
Find the sum of the interior angles of a 15 gon
MA_775_DIABLO [31]
The sum of that is the answer = 3
6 0
3 years ago
Two cars start moving from the same point. One travels south at 24 mi/h and the other travels west at 18 mi/h. At what rate (in
matrenka [14]

Answer:

The rate at which the distance between the two cars is increasing is 30 mi/h

Step-by-step explanation:

Given;

speed of the first car, v₁ = 24 mi/h

speed of the second car, v₂ = 18 mi/h

Two hours later, the position of the cars is calculated as;

position of the first car, d₁ = 24 mi/h  x 2 h  = 48 mi

position of the second car, d₂ = 18 mi/h  x 2 h = 36 mi

The displacement of the two car is calculated as;

displacement, d² = 48² + 36²

                        d² = 3600

                        d = √3600

                        d = 60 mi

The rate at which this displacement is changing = (60 mi) / (2h)

                                                                                 = 30 mi/h

4 0
2 years ago
Use the zero product property to find the equation x^2 + x - 30 = 12
Tom [10]

x=6, add thirty to both sides 6 squared is 36, plus six is 42

4 0
3 years ago
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