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3 years ago

The design shown contains kite ABCD. Which statement is true?

Mathematics

2 answers:

kozerog [31]3 years ago

5 0

Area of ABCD = 10 * 30 + 10 * 10 = 300 + 100 = 400
Area of DBGH = 20 * 30 = 600
Area of DBFC = 1/2(30 * 30) + (10 * 30) + 1/2(10 * 30) = 450 + 300 + 150 = 900
Area of CEBF = 1/2(30 * 30) + (10 * 30) = 450 + 300 = 750

THerefore, option C isthe correct answer.

sveta [45]3 years ago

3 0

Answer:

Step-by-step explanation:

Alright, lets get started.

Area of ABCD :

Area of ABCD =area of ABD + area of BCD

Area of ABCD = $(\frac{1}{2}*20*10) +(\frac{1}{2}*20*30)$

Area of ABCD = 400

Area of DBGH :

Area of DBGH = $20*30 = 600$

Area of DBFC :

Area of DBFC = area of DBC + area of BCF

Area of DBFC = $(\frac{1}{2}*20*30)+(\frac{1}{2}*30*40) = 300+600$

Area of DBFC = 900

Area of CEBF :

Area of CEBF = area of CEBG + area of BGF

Area of CEBF = $300+(\frac{1}{2}*30*30) = 300+450$

Area of CEBF = 750

hence option C is correct : area of DBFC = 900 : Answer

Hope it will help :)

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