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Vaselesa [24]
4 years ago
12

A thermometer is placed in water in order to measure the water's temperature period what would cause the liquid in the thermomet

er to rise?
Physics
1 answer:
Naddik [55]4 years ago
7 0
The thermal energy of the water. Because the water is waaay above Absolute Zero (0K, or -273,15 C) it holds thermal energy or aka the temperature of the water. If the temperature of the water is higher than the one in the thermometer, the heat will 'flow' into the liquid (mostly mercury or modern, it is ethanol), causing the liquid to rise since it's volume increases. The same when te water has lower temperature. The thermal energy of the thermometer will 'flow' in the water and the volume shrinks, causing the liquid to go down. Simple thermodynamics.
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What must be the charge of a particle having E = 81 N/C at 49 mm from the said particle? Express in Coulombs. Use k = 9.0 x 109 
irina [24]

\text{Given that,}\\\\\text{Electric field strength,}~ E  = 81 ~NC^{-1} \\ \\ \text{Distance,}~ d= 49mm = 49 \times 10^{-3} ~m\\ \\\text{Coulomb's constant,}~ k = 9\times 10^9 ~Nm^2 C^{-2}\\\\ \\E= k\dfrac{q}{d^2} \\\\\implies q=\dfrac{Ed^2}{k} =   \dfrac{81 \times \left(49 \times 10^{-3}\right)^2}{9\times 10^9} = 2.1609\times 10^{-11} ~C\\\\\\\text{The charge of the particle  is}~2.1609\times 10^{-11} ~C

7 0
2 years ago
Fill in the blank.
Fofino [41]
It would decrease, hope it helps
8 0
3 years ago
Read 2 more answers
Which of the following statements regarding the moon and Earth is correct?
hoa [83]
It’s Definitely A the other one’s are definitely wrong and I know A is a fact
7 0
2 years ago
Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t
wolverine [178]

Answer:

final velocity =  0.08585m/s

Explanation:

We are taking train cars as our system. In this system no external force is acting. So we can apply the law of conservation of linear momentum.

The law of conservation of linear momentum states that the total linear momentum of a system remains constant if there is no external force acting on the system. That is total linear momentum before = total linear momentum after

total linear momentum before = linear momentum of first train car + linear momentum of second train car

We know that linear momentum = mv

where,

m = mass

v = velocity

thus,

total linear momentum before = m₁v₁ + m₂v₂

m₁ = mass of first train car = 135,000kg

v₁ = velocity of first train car = 0.305m/s

m₂ = mass of first second car =  100,000kg

v₂ = velocity of second train car =  −0.210m/s

Note: Momentum is a vector. So while adding momentum we should take account of its direction too. Here since second train car is moving in a direction opposite to that of the first one, we have taken its velocity as negative.

total linear momentum before = m₁v₁ + m₂v₂

                                                  = 135,000x0.305 + 100,000x(−0.210)

                                                  = 135,000x0.305 - 100,000x0.210

                                                  = 20,175 kgm/s

Now we have to find total linear momentum after bumping. After the bumping both the train cars will be moving together with a common velocity(say v).

Therefore, total linear momentum after = mv

m = m₁ + m₂ = 135,000 + 100,000 = 235,000

total linear momentum before = total linear momentum after

235,000v = 20,175

v =  \frac{20,175}{235,000}

  = 0.08585m/s

8 0
3 years ago
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790 kilometers/hour for a distance of 4,700 kilometers
chubhunter [2.5K]

Answer:

Explanation:

Time = (distance) / (average speed)

Time = (4,700 km) / (790 km/hr) = 5.9494 hours (rounded)

                                                  = 5hrs 56min 58 sec (rounded)

    (4,700 km) / (1.609344 km/mile) = 2,920 miles

Speed = (distance covered) / (time to cover the distance)

                      (2,929 miles) / 5.9494 hours) =  491 miles per hour

5 0
3 years ago
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