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qwelly [4]
3 years ago
8

A tennis ball thrown with a velocity of 25m/s[Fwd] in the horizontal direction from the top of an 80m high building.

Physics
2 answers:
lesantik [10]3 years ago
5 0

Answer:

d hope you get it right

Explanation:

KiRa [710]3 years ago
3 0

Answer:

Explanation:

Ignoring air resistance

1) from vertical rest

s = ½at²

t = √(2s/a)

t = √(2(80)/9.8)

t = 4.040610...

t = 4.0 s

2) d = vt

   d = 25(4.0)

   d = 100 m

3) v² = u² + 2as

   v² = 25² + 2(9.8)(80)

   v² = 2193

   v = 46.8294...

    v = 47 m/s

θ = - 90 + arcsin(25/46.8294)

θ = -57.7339...

θ = 58° below the horizontal

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5 0
3 years ago
Add these measurements, using significant digit rules:<br><br> 1.0090 cm + 0.02 cm = cm
marin [14]

Answer:

1.029

Explanation:

1.0090 can also be looked at as "1.009"

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7 0
3 years ago
If Vx = 7.00 units and Vy = -7.60 units, determine the magnitude of V⃗ .
Juliette [100K]

|V| = 10.33 units and the direction θ = -47.35° or 312.65°.

Given the x and y components of a vector, we can calculate the magnitude and direction from these components.

Applying the Pythagorean theorem we have that the magnitude of the vector is:

|V| = \sqrt{Vx^{2}+Vy^{2}  }

|V| = \sqrt{(7.00units)^{2}+(-7.60units)^{2}} = \sqrt{106units^{2}} = 10.33units

The expression for the direction of a vector comes from the definition of the tangent of an angle:

tan θ = \frac{Vy}{Vx} ------>  θ = arc tan \frac{Vy}{Vx}

θ = arc tan \frac{-7.60units}{7.00units}

θ = -47.35° or 312.65°

6 0
3 years ago
An electric kettle has a power rating of 2.4kW. How long does it take the kettle to heat up 4.5kg of tap water from 28°C to 100°
Schach [20]

Assumption :

- The process is adiabatic

- Heat from electric kettle is constant

- Efficiency of electric kettle is 100%

Q = m • c • ∆T

P • t = m • c • ∆T

2400t= (4.5 kg)(4200 J/kg°C)(100°C - 28°C)

2400t = 1360800

t = 567 s

t = 9.45 min

3 0
2 years ago
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