To solve this problem we will use the related concepts in Newtonian laws that describe the force of gravitational attraction. We will use the given value and then we will obtain the proportion of the new force depending on the Radius. From there we will observe how much the force of attraction increases in the new distance.
Planet gravitational force
Distance between planet and star
Gravitational force is
Applying the new distance,
Replacing with the previous force,
Replacing our values
Therefore the magnitude of the force on the star due to the planet is 
We know that arc length (x(t)) is given with the following formula:
Where r is the radius of the barrel. We must keep in mind that as barrel rolls its radius decreases because less and less tape is left on it.
If we say that the thickness of the tape is D then with every full circle our radius shrinks by d. We can write this down mathematically:
When we plug this back into the first equation we get:
We must solve this quadratic equation.
The final solution is:
It is rather complicated solution. If we asume that the tape has no thickness we get simply:
Answer:
v
2
=v
0
2
+2aΔxv, squared, equals, v, start subscript, 0, end subscript, squared, plus, 2, a, delta, x
Explanation:
Answer:
A) m = F/a = 91.7/9.81 = 9.35 kg
B) m = F/a = 59.2/9.81 = 6.03 kg
C) m = F/a = 33.4/9.81 = 3.40 kg
D) m = F/a = 9.65/9.81 = 0.984 kg
Explanation:
