Three forces acting at a point keep it in equilibrium . If the angle between two of the forces , 3 N and 3 Nis 120°, then the th
1 answer:
Answer:
see attachments
Explanation:
The force necessary to maintain equilibrium depends on the directions of the two forces that are separated by 120°. If both are pointing toward or away from the point, the third force will be pointing that same direction. It will be 120° from the other two, and the same magnitude (3 N).
If the one of the two forces is pointing toward, and the other is pointing away, then the third force will have magnitude 3√3 N, and will be 30° from one of the other forces. This is illustrated in the 2nd attachment.
You might be interested in
The location of the point F that partitions a line segment from D to E (), that goes from <u>negative 4</u> to <u>positive 5,</u> into a 5:6 ratio is fifteen halves (option 4).
We need to calculate the segment of the line DE to find the location of point F.
Since point D is located at <u>negative -4</u> and point E is at <u>positive 5</u>, we have:
Hence, the segment of the line DE () is 9.
Knowing that point F partitions the line segment from D to E () into a <u>5:6 ratio</u>, its location would be:
Therefore, the location of point F is fifteen halves (option 4).
Learn more about segments here:
I hope it helps you!
