An object of mass m moving at a speed of v1 possesses kinetic energy that is equal to KE1. When the object's speed is doubled, t
he kinetic energy becomes KE2. How can you relate KE2, to KE1?
Answer and I will give you brainiliest
Answer and I will give you brainiliest
1 answer:
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Answer:
The energy E is 1603.008 J.
Explanation:
Given that,
Capacitor = 18.4 μF
Voltage = 13.2 kV
We need to calculate the energy
Using formula of energy
.....(I)
We know that,
Put the value of Q in equation (I)
On integration
Put the value into the formula
Hence, The energy E is 1603.008 J.
At the highest point of the trajectory the vertical component will have its zero velocity, and the descent caused by the force of gravity will begin.
Since the ball is thrown with a certain speed, the vertical component reaches its highest point (upwards), until returning to the receiver who will receive the ball with the same vertical component but in the opposite direction (downwards).
Therefore the vertical component will have its highest value at launch.
