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Amanda [17]
3 years ago
6

Solve the equation 169x^2+36=0

Mathematics
1 answer:
KonstantinChe [14]3 years ago
5 0
The answers are 6i/13 and -6i/13. The work it attached below

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F(x)= 7.45x +33.7 at x=-4.3
weeeeeb [17]

To solve this function, all we need to do is substitute -4.3 in for wherever "x" appears and then simplify.

f(x) = 7.45x + 33.7; x = -4.3

f(-4.3) = 7.45(-4.3) + 33.7

f(-4.3) = -32.035 + 33.7

f(-4.3) = 1.665

This means that, when x = -4.3, f(x) = 1.665.

Note: It may help to remember that, in a function such as this, f(x) can be thought of as the "y" value that corresponds to the given "x" value (in fact, when writing it out with words, f(x) is the same as "function of x"). And, if you are given a value for f(x), then the opposite is true. Just substitute in the value given for f(x) and solve for x.

Hope this helps!

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4 years ago
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Aleks04 [339]

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All the angles are different. And It's concave.
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3 years ago
Sin^2(x/2)=sin^2x <br> Find the value of x
Veronika [31]
\sin^2\dfrac x2=\sin^2x
\dfrac{1-\cos x}2=1-\cos^2x
1-\cos x=2-2\cos^2x
2\cos^2x-\cos x-1=0
(2\cos x+1)(\cos x-1)=0
\implies\begin{cases}2\cos x+1=0\\\cos x-1=0\end{cases}\implies\begin{cases}\cos x=-\frac12\\\cos x=1\end{cases}

The first case occurs in 0\le x for x=\dfrac{2\pi}3 and x=\dfrac{4\pi}3. Extending the domain to account for all real x, we have this happening for x=\dfrac{2\pi}3+2n\pi and \dfrac{4\pi}3+2n\pi, where n\in\mathbb Z.

The second case occurs in 0\le x when x=0, and extending to all reals we have x=2n\pi for n\in\mathbb Z, i.e. any even multiple of \pi.
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3 years ago
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