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tigry1 [53]
3 years ago
5

I need urgent help!!

Mathematics
2 answers:
Alex787 [66]3 years ago
8 0

Answer:

B

Step-by-step explanation:

x - 5/8 + 1/8 = 6/8 = -3/8 if u simplify

to simplify u need to see how many times it can be shrunk to do it

hope that helped

elena-s [515]3 years ago
6 0
Tha answer is B , very simple
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A building engineer analyzes a concrete column with a circular cross section. The circumference of the column is 18 \pi18π18, pi
Whitepunk [10]

Answer:

A=81\pi $ m^2

Step-by-step explanation:

Circumference of the column =18\pi $ meters

Circumference of a circle=2\pi r

Therefore:

2\pi r =18\pi $ meters\\2r=18\\r=18 \div 2\\$Radius, r=9 meters

Area of a Circle =\pi r^2

Since radius of the cross section of the column =9 meters

Area of the cross section of the column

=\pi *9^2\\=81\pi $ m^2

5 0
3 years ago
Please help I'm almost out of time ​
Serhud [2]

Answer:

3/2

Step-by-step explanation:

move the 3x to the other side and divide it by 2

3 0
3 years ago
Newton's law of cooling is:
Mnenie [13.5K]

Answer:

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

\frac{du}{dt}= -k (u-T)

We can reorder the expression like this:

\frac{du}{u-T} = -k dt

We can use the substitution w = u-T and dw =du so then we have:

\frac{dw}{w} =-k dt

IF we integrate both sides we got:

ln |w| = -kt +C

If we apply exponential in both sides we got:

w = e^{-kt} *e^c

And if we replace w = u-T we got:

u(t)= T + C_1 e^{-kt}

We can also express the solution in the following terms:

u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}

For this case we know that k =-0.15 hr since w ehave a cooloing, T_{i}= 70 F, T_{amb}=11F, we have this model:

u(t) = (70-11) e^{-0.15t} +11

And if we want that the temperature would be 32F we can solve for t like this:

32 = 59 e^{-0.15 t} +11

21=59 e^{-0.15 t}

\frac{21}{59} = e^{-0.15 t}

If we apply natural logs on both sides we got:

ln (\frac{21}{59}) =-0.15 t

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

7 0
4 years ago
0. The weight of an object on the Moon is about 16.5% of its weight on Earth. The weight of an astronaut on the Moon is 24.75 po
Setler79 [48]

Answer: 150 pounds

Step-by-step explanation:

Let the the astronaut weight on Earth be represented by x.

Based on the information given in the question, thus can be formed into an equation as:

16.5% of x = 24.75

16.5% × x = 24.75

16.5/100 × x = 24.75

0.165x = 24.75

x = 24.75/0.165

x = 150 pounds

The astronaut weigh 150 pounds on Earth.

3 0
3 years ago
You recycled a total of 30 cans and bottles and made $1.80. For cans you get $0.05 and for bottles
Svetlanka [38]

Answer:

27

Step-by-step explanation:

x + y = 30

0.05x + 0.15y = 1.80

x = 30 - y

1.5 - 0.05y + 0.15y = 1.80

0.10y = 0.30

y = 3 (bottles)

x = 27 (cans)

5 0
3 years ago
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