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KATRIN_1 [288]
3 years ago
6

Charlie runs at a speed of 3 yards per second . About how many miles per hour does Charlie run?

Mathematics
1 answer:
Debora [2.8K]3 years ago
6 0
Charlie runs 6.136 mi/hr
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nirvana33 [79]

Answer:

-21

Step-by-step explanation:

8 0
3 years ago
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Need answers for test!!!!! Due today.
Sphinxa [80]

Answer:

100+100=200

160 +80 =240 240+200=440

Step-by-step explanation: first you must add the frist to sides

440+ the rest of the numbers.

6 0
4 years ago
10-mg Atorvastatin Placebo Headache 15 65 No headache 17 3 3. If two different subjects are randomly selected, find the probabil
balu736 [363]

Answer:

0.6384

Step-by-step explanation:

Given that:

10-mg Atorvastatin Placebo Headache  15      65       No headache 17      3

Hence the total of number of patients = 15 + 65 + 17 + 3 = 100 patients

The number of patients with headache = 15 + 65 = 80 patients

Also, C(n, x) is the number of combinations in which n items can be chosen taken x at a time it is given by the formula:

C(n,x)=\frac{n!}{(n-x)!x!}

The the probability that if two different subjects they both had a headache = \frac{C(80,2)}{C(100,2)}=\frac{\frac{80!}{(80-2)!2!} }{\frac{100!}{(100-2)!2!} }  =\frac{3160}{4950}=0.6384

4 0
3 years ago
Find the area of the trapezoid below to the nearest tenth.
kondor19780726 [428]

Answer:

Area of trapezoid = 67.6 square units

Step-by-step explanation:

Area of a trapezoid is given by the expression,

Area of the trapezoid = \frac{1}{2}(b_1+b_2)h

Here, b_1 and b_2 are the parallel sides of the given trapezoid.

And 'h' = Height between the parallel sides

From the given triangle ABE,

m(∠ABE) = m(∠ABC) - m(∠EBC)

m(∠ABE) = 120° - 90°

               = 30°

By applying cosine rule in the given triangle,

cos(30°) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

\frac{\sqrt{3} }{2}=\frac{BE}{AB}

\frac{\sqrt{3} }{2}=\frac{BE}{6}

BE = 3\sqrt{3} units

By applying sine rule in ΔABE,

sin(30°) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

\frac{1}{2}=\frac{AE}{AB}

\frac{1}{2}=\frac{AE}{6}

AE = 3 units

Length of b_1=BC=10

Length of b_2=AD=(AE+EF+FD) [AE = FD, since given trapezoid ABCD is an isosceles trapezoid]

                b_2=3+10+3

                b_2=16

Height between the parallel sides h=3\sqrt{3}

Area of the trapezoid = \frac{1}{2}(BC+AD)BE

                                    = \frac{1}{2}(10+16)(3\sqrt{3})

                                    = 39\sqrt{3}

                                    = 67.6 square units

8 0
3 years ago
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Pani-rosa [81]

Answer:

B.

Step-by-step explanation:

Just did on edge

6 0
3 years ago
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