The slope of this line is -1/3. To determine slope, you can remember the phrase rise over run. To elaborate, this example has points on (0,4) and (6,2). Use rise over run to solve this.
Starting from the (6,2) go up two units to be on the same line which (0,4) is on. Count the units going left until you reach that point. You should have come up with 6. Technically, the slope would be -2/6 because the line is going downwards, but it can be simplified to -1/3.
An actual equation you can use is y2-y1/x2-x1: 6-4/0-3= -2/6 = -1/3
Answer:
Given any straight line and a point not on it, there "exists one and only one straight line which passes" through that point and never intersects the first line, no matter how far they are extended. This statement is equivalent to the fifth of Euclid's postulates, which Euclid himself avoided using until proposition 29 in the Elements. For centuries, many mathematicians believed that this statement was not a true postulate, but rather a theorem which could be derived from the first four of Euclid's postulates. (That part of geometry which could be derived using only postulates 1-4 came to be known as absolute geometry.)
Also draw the line straight line them up. To me it would be best if you use a ruler.
Answer:
it is D
Step-by-step explanation:
I know things dude. I got your back :-)
Answer:
−15x2+23x−6
Step-by-step explanation:
(3x−1)(−5x+6)
=(3x+−1)(−5x+6)
=(3x)(−5x)+(3x)(6)+(−1)(−5x)+(−1)(6)
=−15x2+18x+5x−6
=−15x2+23x−6
