Answer:
61.22m
Explanation:
Maximum height in projectile is expressed as;
H = u²sin²θ/2g
u is the speed
g is the acceleration due to gravity
θ is the angle of projection
Substitute the given values into the formula;
H = u²sin²θ/2g
H = 40²sin²60/2g
H = 1600(0.8660)²/2(9.8)
H = 1600(0.8660)²/2(9.8)
H = 1,199.9/19.6
H = 61.22m
Hence the maximum height achieved by the ball is 61.22m
Answer:
The current through it will also decrease to half of its former value because according to Ohm's law the current flowing through a resistor is directly proportional to the potential difference applied across its ends provided that the temperature and some other necessary conditions remain constant.
This is mathematically represented as follows;

The current is thus given as

if R is constant and V is reduced to half, then we have the following;

Simplifying further we obtain

Equation (3) shows that the current I is also reduced to half.
First, determine the mass of the object by dividing its weight on Earth by 9.8 m/s² as shown below,
m = 250 N / 9.8 m/s² = 25.51 kg
Then, multiply the obtained mass by the acceleration due to gravity (g) on Pluto.
W (in Pluto) = (25.51 kg) x (0.61 m/s²) = 15.56 N
Therefore, the object will only weigh 15.56 N.