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Delicious77 [7]
3 years ago
15

What determines the path that an object in projectile motion follows? (Ignore air resistance)

Physics
1 answer:
blondinia [14]3 years ago
8 0
Gravity only determines the path in projectile motion
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Energy of motion is.
lidiya [134]
The answer is C. Potential energy is when an object is at rest.
Kinetic is when an object is in motion.
5 0
4 years ago
Read 2 more answers
For an extended object, the weight force can be considered to act at which point?
JulsSmile [24]

Answer:

At the center of the object

At the end of the object farthest away from the ground

At the center of gravity of the object

At end of the object closest to the ground

Explanation:

5 0
3 years ago
What is the relationship between the wavelength of the peak (maximum) of the Gaussian curve and the temperature in degrees Kelvi
Tomtit [17]

Answer:

\lambda_{max}=\frac{b}{T}

Explanation:

Wien's displacement law states that the radiation of the black body curve for different temperatures will give peak values at different wavelengths and this wavelength is related inversely to the temperature.

Formally the law of Wien displacement states that the black body's spectral radiation per unit of wavelength, will give peaks at the wavelength of  \lambda_{max} which is given by the mathematical expression.

\lambda_{max}=\frac{b}{T}

Here, b is proportionality constant  with value of 2.897771955...\times 10^{-3} mK

The wavelength of the peak of the Gaussian curve is inversely related to temperature in degree kelvin.

3 0
3 years ago
Romeo (81.0 kg) entertains Juliet (53.0 kg) by playing his guitar from the rear of their boat at rest in still water, 2.70 m awa
den301095 [7]

Answer:

0.64 m

Explanation:

The first thing is calculate the center of mass of the system.

X_{cm}= \sum_{n=1}^{n}\frac{X_n\times M_n}{M_n}

now multiplying every coordinate x by the mass of each object (romeo, juliet and the boat) and dividing all by the total mass  taking by reference the position of juliet.

X_{cm}=\frac{53\times0 +81\times2.7+79\times1.35}{53+81+79}

X_cm = 1.4589 m

When the forces involved are internals, the center of mass don't change  

After the movement the center of mass remains in the same distance from the shore, but change relative to the rear of the boat.

X_{cm}=\frac{79\times1.35+(81+53)\times2.7}{53+81+79}

X_cm= 2.10 m

this displacement is how the boat move toward the shore.

2.10-1.46= 0.64 m

5 0
3 years ago
A 50-kg toboggan is coasting on level snow. As it passes beneath a bridge, a 20-kg parcel is dropped straight down and lands in
timama [110]

Answer:

KE2/KE1=0.71

Explanation:

By conservation of the linear momentum:

m1*V1 = (m1+m2)*V2

Solving for V2:

V2 = \frac{m1}{m1+m2}*V1

The kinetic energies are:

KE1=1/2*m1*V1^2

KE2 = 1/2*(m1+m2)*V2^2

KE2 = 1/2*(m1+m2)*(\frac{m1}{m1+m2}*V1)^2

Simplifying:

KE2 = 1/2*\frac{m1^2}{m1+m2}*V1^2

The ratio will be:

KE2/KE1=\frac{1/2*\frac{m1^2}{m1+m2}*V1^2}{1/2*m1*V1^2} =\frac{m1}{m1+m2}

KE2/KE1=0.71

5 0
3 years ago
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