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2 years ago

What determines the path that an object in projectile motion follows? (Ignore air resistance)

Physics

1 answer:

blondinia [14]2 years ago

8 0

Gravity only determines the path in projectile motion

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A garage door opener has a power rating of 350 watts. If the door is in operation for 30 seconds, how many joules of energy are

Ksju [112]

Because of the hint we can conclude what equation we need to solve this problem. We have power and duration that means that we need to express energy:

1 joule = 1watt * 1 second
or
E (energy) = P (power) * t (time duration)
E = 350 * 30 = 10500 joules.

7 0

2 years ago

Monochromatic light of wavelength, lambda, is traveling in air. The light then strikes a thin film having an index of refraction

kumpel [21]

Answer:

The correct option is H

Explanation:

From the question we are told that

The index of refraction of coating is $n_1$

The index of refraction of material is $n_2$

Generally the condition for constructive for a thin film interference is mathematically represented

$2 * t = [ m + \frac{1}{2}] \frac{\lambda}{n_1 }$

Here t represents the thickness

For minimum thickness m = 0

$2 * t =0 + \frac{1}{2}\frac{\lambda}{n_1 }$

=> $t =\frac{\lambda}{4n_1 }$

3 0

2 years ago

Why is it advised not to hold the thermometer by its bulb while reading it?

Fiesta28 [93]

Because your body heat might change the temperature

7 0

2 years ago

Read 2 more answers

A hockey puck sliding on smooth ice at 4 m/s comes to a 1-m-high hill. Will it make it to the top of the hill?

solniwko [45]

Answer:

No it will not make to the top of the hill

Explanation:

From the question we are told that

The velocity is $v = 4 \ m/s$

The height of the hill is $h = 1 \ m$

Generally from the law of energy conservation we have that

The kinetic energy of the pluck at the level position = The potential energy of the pluck at the maximum height the pluck can get to

$\frac{1}{2} * m * v^2 = m * g * h_{max}$

=> $\frac{1}{2} * v^2 = g * h_{max}$

=> $h_{max} = \frac{0.5 * v^2}{g}$

=> $h_{max} = 0.8163 \ m$

Given that the maximum height which the pluck can get to at this speed given in the question is less than the height of the hill then conclusion will be that the pluck will not make it to the top of the hill

3 0

2 years ago

A 35.0-kg dolphin decelerates from 12.0 to 7.50 m/s in 2.30 s to join another dolphin in play. What average force was exerted to

Stels [109]

Answer:

68.5N

Explanation:

When the dolphin decelerates from 12m/s to 7.5 m/s within 2.3s. Then its acceleration is:

$a = \frac{\Delta v}{\Delta t} = \frac{7.5 - 12}{2.3} = -1.96 m/s^2$