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Delicious77 [7]
3 years ago
15

What determines the path that an object in projectile motion follows? (Ignore air resistance)

Physics
1 answer:
blondinia [14]3 years ago
8 0
Gravity only determines the path in projectile motion
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Which of the following is true of an adiabatic process?
poizon [28]

Adiabatic process is that process in which heat of a closed system will remain conserved or we can say that system can not exchange its thermal energy from its surrounding

So here from 1st law of thermodynamics we can say

\Delta Q = \Delta U + W

since we know that

\Delta Q = 0

so we will have

0 = \Delta U + W

so we have

-\Delta U = W

so here correct answers are

<em>A. -ΔU = W  </em>

<em>B. Heat is constant. </em>

7 0
3 years ago
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Number of vibrations (waves) in an amount of time
m_a_m_a [10]

Answer:

I think frequency not sure though

How frequently a wave or vibration occurs during a span of time, determines the waves frequency. Frequency is the number of waves per unit time. The unit for frequency if a Hertz ( 1/second). The speed a wave travels is the wavelength multiplied by this frequency. The amplitude of a wave is the maximum distance the wave is displaced.

5 0
2 years ago
Will Give Brainliest and 25 Points
Vikentia [17]

This is the Doppler effect.

1. As the sound leaves the horn the sound waves are at first close to each other and as they move outwards they become further apart. The closer the sound waves are the louder the noise.

As the car gets the closer the sound waves get closer, so the horn becomes louder.

2. As the horn moves away, the sound waves become less frequent, causing the pitch to get lower.

5 0
3 years ago
[1] The assembly starts from rest and reaches an angular speed of 150 rev/min under the action of a 20-N force T applied to the
ExtremeBDS [4]

Answer:

t = 5.89 s

Explanation:

To calculate the time, we need the radius of the pulley and the radius of the sphere which was not given in the question.

Let us assume that the radius of the pulley (r_p) = 0.4 m

Let the radius of the sphere (r) = 0.5 m

w = angular speed = 150 rev/min = (150 × 2π / 60) rad/s = 15.708 rad/s

Tension (T) = 20 N

mass (m) = 3 kg each

\int\limits^0_t {Tr_p} \, dt=H_2-H_1\\( Tr_p)t=4rm(rw)\\( Tr_p)t=4r^2mw

t = \frac{4r^2mw}{Tr_P}

Substituting values:

t = \frac{4r^2mw}{Tr_P}= \frac{4*(0.5)^2*3*15.708}{20*0.4}=5.89s

7 0
3 years ago
Read 2 more answers
A simple electric motor consists of a 220-turn coil, 4.4 cm in diameter, mounted between the poles of a magnet that produces a 9
Verdich [7]

Answer:

M = 5.01\ A.m^2          

Explanation:

It is given that,

Number of turns in the coil, N = 220

Diameter of the coil, d = 4.4 cm

Radius of the coil, r = 2.2 cm = 0.022 m

Magnetic field produced by the poles of magnet, B=96\ mT=96\times 10^{-3}\ T

Current flowing in the coil, I = 15 A

Let M is the coil's magnetic dipole moment. Its formula is given by :

M=N\times I\times A

M=220\times 15\times \pi (0.022)^2

M = 5.01\ A.m^2

So, the coil's magnetic dipole moment is 5.01\ A.m^2. Hence, this is the required solution.

4 0
3 years ago
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