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3 years ago

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While wearing rubber-soled shoes, you rub a helium balloon on your sweater. The balloon becomes negative charged. Now release th

e balloon. When the balloon is at the ceiling, you are
A) negatively charged.B) electrically neutral.C) positively charged.D) discharged.

1 answer:

Sonja [21]3 years ago

6 0

Answer: you are creatively creating static electricity.

Explanation:

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Answer:

The beam of light is moving at the peed of:

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Given:

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Solution:

Angular velocity, $\omega = \frac{d\theta'}{dt} = 2\pi n = 2\pi \times 4 = 8\pi$ (1)

Now, in the right angle in the given fig.:

$tan\theta' = \frac{y}{3}$

Now, differentiating both the sides w.r.t t:

$\frac{dtan\theta'}{dt} = \frac{dy}{3dt}$

Applying chain rule:

$\frac{dtan\theta'}{d\theta'}.\frac{d\theta'}{dt} = \frac{dy}{3dt}$

$sec^{2}\theta'\frac{d\theta'}{dt} = \frac{dy}{3dt} = (1 + tan^{2}\theta')\frac{d\theta'}{dt}$

Now, using $tan\theta = \frac{1}{m}$ and y = 1 in the above eqn, we get:

$(1 + (\frac{1}{3})^{2})\frac{d\theta'}{dt} = \frac{dy}{3dt}$

Also, using eqn (1),

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2 years ago

Through what vertical height is a 50 N object moved if 250 J of work is done lifting it against the gravitational field of Earth

zimovet [89]

5m

Explanation:

Given parameters:

Weight of object = 50N

Work done in lifting object = 250J

Unknown:

Vertical height = ?

Solution:

The work done on an object is the force applied to lift a body in a specific direction.

Work done = force x distance

Weight is a force in the presence of gravity;

Work done = weight x height of lifting

Height of lifting = $\frac{work done }{weight}$

Height of lifting = $\frac{250}{50}$ = 5m

The vertical height through which the object was lifted is 5m

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Work done brainly.com/question/9100769

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3 years ago

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ryzh [129]

Balance:
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a car driving at 10 miles per hour in constant velocity
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your brother sprinting across the kitchen
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Answer:

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