Answer: 7.07 m/s
Explanation:
Mass of runner = 60 kg runner
Kinetic energy = 1500J
Speed of runner = ?
Recall that kinetic energy is the energy possessed by a moving object, and it depends on its mass and speed by which it moves.
Hence, K.E = 1/2 x mass x (speed)^2
1500J = 1/2 x 60kg x (speed)^2
1500J = 30kg x (speed)^2
(speed)^2 = 1500J/30kg
(speed)^2 = 50
To get the value of speed, find the square root of 50
speed = √50
speed = 7.07 m/s
Thus, the runner moves as fast as 7.07 m/s
Answer: option D
Explanation: The combination of 2 waves to produce a resultant effect at a point is known as interference.
If the waves are in the same direction, the resultant effect is of a larger magnitude, this is called constructive interference which is still a progressive wave.
If the resultant effect brings about cancellation of both waves, we have a destructive interference which forms a standing wave.
Answer:
<h2>0.432mA</h2>
Explanation:
Current produced by the solar cells of the pocket calculator is expressed using the formula I = Q/t where;
Q is the charge (in Columbs)
t is the time (in seconds)
Given parameters
Q = 4.2C
t = 2.7 hrs
t = 2.7*60*60
t = 9720 seconds
Required
Current produced by the solar cell I
Substituting the given values into the formula;
I = 4.2/9720
I = 0.000432A
I = 0.432mA
Hence, the current in milliamperes produced by the solar cells of a pocket calculator is 0.432mA
Answer:
The magnitude of the rate of change of the flux through the coil is 2.82 x 10⁻³ T.m²/s
Explanation:
Given;
radius of coil, r = 8 cm = 0.08 m
number of turns of the coil, N = 110 turns
the induced emf through the coil, E = -310mV
The induced emf through the coil is given by;

Where;
dФ/dt is the magnitude of the rate of change of the flux through the coil

Therefore, the magnitude of the rate of change of the flux through the coil is 2.82 x 10⁻³ T.m²/s
The velocity of the particle is given by the derivative of the position vector:

(a) The particle is moving in the <em>x</em>-direction when the <em>y</em>-component of velocity is zero:

But we want <em>t</em> > 0, so this never happens, unless 2<em>c</em> = <em>d</em> is given, in which case the <em>y</em>-component is always zero.
(b) Similarly, the particle moves in the <em>y</em>-direction when the <em>x</em>-component vanishes:

We drop the zero solution, and we're left with

In the case of 2<em>c</em> = d, this times reduces to <em>t</em> = <em>c</em>/(6<em>c</em>) = 1/6.